Mechanical Engineering: Equilibrium of Rigid Bodies (8 of 30) Find F=? T=? Ex.3, 2-Dimensions

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In this video I will find the tension of a cable and forces of the wheels (A and B) of a cart on incline.

Next video in this series can be seen at:
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great Lecture Dean Van Biezen... great series on Mechanical Engineering.. It won't be long before I graduate from VIT .... what's VIT ?... well, you've heard of MIT.. yes?... well VIT is the VanBeizen Institute of Technology .... and you are the DEAN.... congrats on a diverse collection of all things Technical.... astronomy, chemistry, algebra, calculus, Matrices, probabilities, etc etc.... Physics... Mechanical Engineering... and so many Video Lectures with a multitude of Solved truly Amazing Michel !! ... thank you... for the record I'm 61 years old and have a B.S. Degree in Physical Science from Michigan State University. But I truly enjoyed all the science courses that you present here. I try to refresh my knowledge.. but as one Professor once said, "It's NOT what you Know that matters... it's what you UNDERSTAND that matters" .. and that's where your talent for teaching Understanding truly reveals itself... You teach UNDERSTANDING.... .. Good luck and more later.... Peace always...

ptyptypty
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it would be much easier if we equate the moment around c to zero, this way Fa and Fb will have equal moments around c, and since they are of the same perpendicular distance to c, they must be equal in magnitude. Btw, great leacture

amarsherif
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thank u sir what a huge help big great from iraq

hazimrasheed
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What if the object moves at negative x-direction? Would the force on B become smaller or still remain the same?

wu
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What if the given unit of measure is Pounds (lb)? Do I need to convert it to kg first before multiplying it to 9.8? Or can I multiply it directly?

mildredoliva
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Hi Michel, thanks for the great videos, I was just curious why the forces worked out equal, I thought the reaction force at the lower (front reaction force B) wheel,  would be more, and the higher wheel (reaction force A) would be a lower force. You would think the lower wheel is carrying more weight because of the slope.

rckygrhm
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why you take mgsin@ in the X direction and mgcos@ in the Y? Can"t I choose the opposite option?

sk.hasantanvirulislam
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thanks for all of your amazing videos.
I have question about this video. when you were calculating the moment at point O I thing the distance for (mg)(sin30) is (2m) which is what you used in the video, but for the distance of (mg)(cos30) should be 1m and in the video you are using 2. The perpendicular distance between the force and the point that you are calculating the moment about is 1m.

I hope you can do some videos about rotating the coordinates axis and how do we choose theta where to be. this will be helpful.
thanks again professor

salaldin
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i did not find and i will not find lecture you did not explain it very well

hamadalyami