PALINDROME NUMBER |Leet Code | CFAM | #leetcode #cfam #leetcode009 | Coder From Another Mother

Leetcode problem 009 Palindrome Number Solution using

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Introduction:
The provided Python code defines a class named Solution with a method reverse, which is designed to reverse the digits of an input integer. The implementation takes into consideration the sign of the integer and handles potential overflow scenarios.

Code Breakdown:

Initialization:

Variables: The code initializes three crucial variables: r to store remainders, temp to preserve the original value of x, and s to store the reversed integer.
Handling Negativity: If the input integer x is negative, its absolute value is considered. This simplifies the reversal process, as the sign is managed later in the code.
Reversing the Integer:

While Loop: A while loop is employed to iterate through the digits of the integer x.
Digit Reversal: In each iteration, the code calculates the remainder (r) when dividing x by 10. The reversed integer s is then updated by multiplying its current value by 10 and adding the remainder. This iterative process effectively constructs the reversed number digit by digit. Simultaneously, x is updated by integer division by 10, progressively eliminating the last digit.
Handling Overflow and Sign:

Overflow Check: The code checks if the reversed integer s surpasses the maximum value of a 32-bit signed integer (pow(2, 31)).
Result Determination:
If overflow is detected, the function returns 0.
If no overflow occurs:
If the original number (temp) was non-negative, the function returns the reversed integer s.
If the original number was negative (temp was negative), the function returns the negative of the reversed integer (-1 * s). This ensures the preservation of the sign in the reversed result.
Conclusion:
In summary, the provided Python code offers a robust solution for reversing the digits of an input integer. Its careful consideration of sign and overflow scenarios enhances its reliability in diverse use cases.

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