Lines and Angles Class 9 | Lines & Angles Trick | Class 9 Chapter 6 #fun #youtubeshorts #shorts #yt

Lines and Angles Class 9 | Lines & Angles Trick | Class 9 Chapter 6 #fun #youtubeshorts #shorts #yt
@Mathsiseasy
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Chapter 6 Lines and angles
Ch 6 Introduction
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angle sum property of Triangle
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foundation

[shar]

First produce A to line BC name that point P
now 35+45+p=180 (angle sum property) so P=100 now there are 2 triangle P+angle xpc =180(linear pair)so xpc=80
Now by exterior angle property x=140 ANS

[Ishika_dahiya]

Ye to jabardast trick ha was hilarious 😂

[raheemsaifi]

Mam ksi point ke cordinate kse likhte h uska video bnaye plzzz

[Badalseth]

Ek angel bisector draw kr lo angle B ka
Aur phir ext. angle property laga do...bs aa zayega ..

[StudyingIshan]

This is pretty simple..we know this figure is a quadrilateral by 4 sides so all of its angles would be 360⁰. So sum up all angles, which includes reflex X. Find reflex x and then subtract it from 360 (as it is reflex) to get x

[shabanamumtaz]

That ooh Bhaisaaaab & Ye toh zabardast hai was😂😂😂😂

[vincenzgo]

Ye kaise hua 😅 iska alag se video dalna detail mei

[kanhaiyakumar]

Didi tric ke sath sath bachche ko resion bhi dikhaiye nahi aata to hamse Sikh lo drow aline between 45 and x angle

[adarshraj]

Thx ma’am this was the question from rd sharma

[Sny-tjuh]

BAHI YE.... KONSA BACK GROUND SOUND HAI

[Sny-tjuh]

EF || CD and CE is the traversal.
then
angle ECD + CEF = 180° ( consecutive interior angle)

ECD + 130° = 180°

ECD = 180°-130° = 50°

again AB || CD and BC is transversal.
then,

∠ ABC = ∠ BCD (alternate interior angle)

70° = x° + 50°

(∠ BCD = ∠ BCE + ∠ ECD)

x° = 20°

[renutomar]

Wah aise to paas ho jayenge paas hi nahi top karenge

[gamehacks]

Maam ka ba-bye bhoot cute lagta hai yaaar

[JohnsonEkka-txdw]

Lekin reasoning me alpha beta gama likhenge kya😅

[Himanshusagar-gbvx]

Its simple, just we have to produce line CD to E, then in ∆EBC
∠B = 45°, ∠C = 60°, ∠BEC = 180° - 45° -60° = 75°

∠AED+∠BEC = 180° ( LINEAR PAIR )
∠AED = 180° - 75° = 105°

NOW, IN ∆ ADE
∠A = 35°
∠AED = 105°

:. ∠A + ∠AED = x ( theorem, an exterior angle is equal to two interior angles of a triangle )

35° + 105° = x
X = 140°

[riteshpsdhan]

I think ihan per construction se vi yeh ho sakta tha

[ranjukumari]

💯 marks for overreacting 😂😂😂😂😂😂
Edit:- I got 111 likes

[gurpreetkaur.kaur.]

Bruh its simple just use the rule the sum of interior angles is equal to the exterior angles😂