Decorators with arguments : Python tutorial 176

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This video is all about 'decorators with arguments'.

[anilalmeida]

Hi Harshit, could you also have a session on pandas, numpy please. Your teaching methods are great. Thanks a lot

[rishisharma]

Today I can tell to my friends that I know something that u don't know 😊

[forestfaishion]

Bhot achhha smjhate hai sir

I wanna a request that please guide us in use of this all things what u taught us


Love u sir

[Shubham-djk]

from functools import wraps
def
def decorator(function):
@wraps(function)
def wrapper(*args, **kwargs):
if all([type(arg) == data_type for arg in args]):
return function(*args, **kwargs)
else:
return "Invalid Argument"
return wrapper
return decorator

@only_data_type_allow(str)
def string_join(*args):
string = ''
for arg in args:
string += arg
return string

@only_data_type_allow(int)
def number_add(*args):
return sum(args)



print(string_join("Shubham", "Raut"))
print(number_add(1, 2, 3, 4, 5))

[thedeadengineer]

For more clarification, you can also refer this video :

[padhaiparcharcha]

sir list comprehension use nhi kar sakte kya??

[bytetronics]

why do you need that big and complex decorators function just to pass only strings?
This is much better. Actually we don't need decorators only. I showed it using decorators because this is a part of decorators chapter
Code:

from functools import wraps
def allow_string_only(func_name):
@wraps(func_name)
def wrapper_func(*args, **kwargs):
return func_name(*args, **kwargs)
return wrapper_func

@allow_string_only
def add_str(*args):
string=''
for i in args:
if type(i)==str:
string+=i
# else:
# return "invalid input" # add or remove these two lines of else statement
return string

print(add_str('abc', 'def')) # output is abcdef removing the else statement
print(add_str('abc', 'def', 8, [1, 2])) # output is still abcdef removing the else statement
print(add_str('abc', 'def', 8, [1, 2, 3])) # output is 'invalid input' adding the else statement

[sushantbhagat]

5:11 iska matlab samjhe Dya ki harshit railway station ka pass rahta hai.

[RakibSUST]

why there is an error when i use just --> def wappeed(*args)

[yugie]

Sir, in above program if we want make it into only integer input function then it is throwing error as due to string=' ' .
What to do if we want to make a single program which can accept only that data type which is mentioned in @ decorator?

[irfanamin]

Ye mai nai kiya hy hm koi bhi data type pass kr sakty hain check it


from functools import wraps

def only_int_allow(any_function):
@wraps(any_function)
def wraper_function(*args, **kargs):
if all(type(i)==type(args[0]) for i in args):#jb sub datatypes 1 jaisi hon gi tb hi next function call ho ga
return any_function(*args, **kargs)
else:
return "Invalid Arguments"
return wraper_function



@only_int_allow
def add_all(*args):
total =0
for i in args:
total+=i
return total
print(add_all(1, 2, 3, 4, 5))


print("\n")
@only_int_allow
def add_all_strings(*args):
total =""
for i in args:
total+=i
return total
", "Irfan ", "Amin"))

print("\n")
@only_int_allow
def add_all(*args):
total =[]
for i in args:
total+=i
return total
print(add_all([1, 2], [3, 4], [5, 6]))

[anshu_elu]

sir you are doing very well but please when you describing please describe flow control

[lalitsaini]

I got a error in if block
It says nameError : name 'function' is not defined how i remove it please tell me

[shikharagrawal]

What if we want to pass multiple datatypes to the decorator? Like we want to add numbers and the number should be either int or float?

[anuragvarnwal]

I write below code and i get "Invalid argument" output all the time :( please help.
from functools import wraps


def

def decorator(func):
@wraps(func)
def wrapper(*args, **kwargs):
if all([type(arg) == int for arg in args]):
return func(*args, **kwargs)
return "Invalid arguments"
return wrapper
return decorator


@only_data_type_allow(str)
def add_all(*args):
string = ''
for i in args:
string += i
return string


print(add_all('anurag', ' varnwal'))

[PankajDas-mwuq]

Agar keyword argument pass nhi kra skte, to **kwargs ka use ku kr rhe ho

[priyankakurve]

i am getting error
File "<ipython-input-7-9c093bf84ca9>", line 5
if(all[type(arg) == data_type for arg in args]):
invalid syntax in for

[dayanand]

PLease explain the flow of below program:


def decodecorator(dataType, message1, message2):
def decorator(fun):
print(message1)
def wrapper(*args, **kwargs):
print(message2)
if all([type(arg) == dataType for arg in args]):
return fun(*args, **kwargs)
return "Invalid Input"
return wrapper
return decorator


@decodecorator(str, "Decorator for 'stringJoin'", "stringJoin started ...")
def stringJoin(*args):
st = ''
for i in args:
st += i
return st


@decodecorator(int, "Decorator for 'summation'\n", "summation started ...")
def summation(*args):
summ = 0
for arg in args:
summ += arg
return summ


print(stringJoin("I ", 'like ', "Geeks", 'for', "geeks"))
print()
print(summation(19, 2, 8, 533, 67, 981, 119))

[Gamers_adda]

Beginners ki to halat kharab hogyi bhai ynha

[jitenvadhavana]

Itna deep me mt jao bhai. Kuch smj nhi aa raha.