Quadratic Spline | Interpolation | Numerical Computation

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your bounds for (i) doesn't seem correct. If we are using (Z_i+1) then we would stop at z_3, since when i = 2, Z_(i+1) = Z_(3), However we don't have x_3, y_3. So It would make more sense to bound i to be less than or equal to 1, not 2. when i = 1, Z_(i+1) = Z_2. Which would also be our final Z. if you set some variable k = i + 1, then you can bound k to being less than or equal to 2.

nicholasmartinez
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Loves from Turkey <3 Awesome video .

burakgecer
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Thanks so much. What a nice and wonderful Job....am so blessed. Thanks so much. You have my subscription. Notify me always with all.

muwongeevanspaul
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you teach very well but little slow, i watch at 2x but it is still slow.
and you donot covers cubic splines.

LOVEPREETSINGH-xhuz
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The method and everything is easy but the formula 😵

DeepakYadav-ysdg