Chain rule and tree diagrams of multivariable functions (KristaKingMath)

Показать описание

Learn how to use tree diagrams to help you write out the formula for the partial derivative of a multivariable function.

● ● ● GET EXTRA HELP ● ● ●

● ● ● CONNECT WITH KRISTA ● ● ●

Hi, I’m Krista! I make math courses to keep you from banging your head against the wall. ;)

Math class was always so frustrating for me. I’d go to a class, spend hours on homework, and three days later have an “Ah-ha!” moment about how the problems worked that could have slashed my homework time in half. I’d think, “WHY didn’t my teacher just tell me this in the first place?!”

Рекомендации по теме

Комментарии

I have officially passed 2 of my classes with good grades thanks to you. I appreciate your clear and quick explanation. All people can learn but not a lot of people can teach. You have a gift. Thanks again!

armenomidfar

I wish I had a teacher like you at my college! Love how you explain and your handwriting is beautiful! ♡

AA-xkkx

yes! if dy/dt was negative, you'd end up with a difference instead of a sum. We just put the plus sign there, because it still allows you to consider the sign. Because if dy/dt is negative, then you'd get +(-dy/dt), and you'd end up with the negative sign in the end. so it still works. i hope that makes sense, and i'm glad you liked the video!! :D

kristakingmath

I spent 50 minutes with my professor without real understanding and I couldn't be better without you.

khaled

Your website Math services are outstanding! I wish you much success Krista! you deserve the best! Thanks for sharing too

instaminox

Very nice videos. Of your videos I have watched, your videos are MUCH more concise and helpful then the majority of calculus videos out there! Thanks

treinveracity

This is really clear, way better than my prof, thanks!

nairongdu

Just discovered your videos and they are SUPER helpful!! I especially like how detailed you are. THANK YOU!

agarza

because du/dt means that you're taking the derivative of u with respect to t, but you can only do that when you have a single variable. in this case, because we have two variables (x and y), which means you can only take partial derivatives of u, one with respect to x and another with respect to y. when you add the partials together to show the derivative of u with respect to t, you still have to indicate that it's made up of partial derivatives, so you use partial u / partial t.

kristakingmath

I only took the very basic differential and integral calc in college, and although I did well in the classes, I didn't quite have a fundamental grasp of anything higher level.

I happened to stumble upon this video, and somehow, so many things clicked in place. I really understand the math now. Thank you.

alg