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If `cos^-1 (x/2)+cos^-1(y/3)=theta, then (x^2-12xycostheta+4y^2=` (A) 36 (B) `-36sin^2theta`
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If `cos^-1 (x/2)+cos^-1(y/3)=theta, then (x^2-12xycostheta+4y^2=` (A) 36 (B) `-36sin^2theta` (C) `36sin^2theta` (D) `36cos^2theta`
If `cos^-1 (x/2)+cos^-1(y/3)=theta, then (x^2-12xycostheta+4y^2=` (A) 36 (B) `-36sin^2theta`
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