A-Level Pure Mathematics May June 2020 Paper 12 9709/12

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Remember! The most important thing right now is to understand how to get to the answers and not the answers itself. If you can understand and go through the question step by step, then you can do any question when the time comes.

[xter]

Q11 part b. Was implicit differentiation important for this question? I think it is an application of p3!. If we found out the gradient of pc first then we could found found out the gradient of tangent. M1×m2=-1?

[hayley]

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[thecyberhawk]

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[SylionGFX]

This actually saved me, got to learn so much from just completing one paper, will definitely be checking out more of you videos + I had my exam in just an hour or so and you were the only one that helped me. ThankYou!

[Noor-iilk]

THANK GOD FOR YOU. Watching your videos to prepare makes my life so much easier

[parinaramjee]

Thank you so much. This really explained a lot of concepts that I was struggling with. I'd really appreciate it if you did a tutorial on the specimen paper 1 for 2020 (9709_y20_sp_01)

[pearlofillusions]

From time to time I feel like you are speaking French, though I know it's all English😅 Thanks a lot for these videos, they do help a lot!

[jannatbarkaat]

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[shakthirajendran]

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[nellyteekenny]

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[anishsookur]

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[ProEpicGuyac]

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[wowowoweeee]

8 a) why is 1 considered the radius of the cylinder? shouldn't it be 1/2?
since radius is half of the diameter?

[minnahyassin]

hi, i want to say thanks for the video also could you please put a link for the formula sheet that you have? thank you!

[MahinKhattak]

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[divyashenybala]

Hello, for Q11c why did we equate y-2/x-1=0/1 ?thanks

[nourghit]

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[zarbakhtarifhabib]

When will you solve more papers i.e 2018 🥺🥺 you're an angel sent for students like me 😇😇

[pomi]

1:05:31 i dont think this question makes any sense mathematically speaking. A mathematical rule i learned while studying radians is that the perpendicular bisector of two points touching a circle (here P and Q) MUST pass through the center of the circle and at the intersection of the tangent of both circles. And in the rules of intersection points, to find the coordinates of a point we can substitute its equation into the equation of the circle, for example the y=.... of perpendicular bisector we can substitute it into the y of eq. of the circle. But if you substitute all that you get T as (7, 2) because perpendicular bisector equation is y=2. If anyone can help me understand this question it will be much appreciated .

[luanadatrindade]

The cosine rule that you used for question 7(a) is to find a missing angle right? Shouldn’t we use a^2 = b^2 + c^2 - 2bcCOS(A) ?