filmov
tv
DFA for ab^na^m where n is greater than or equal to 2 ,m is greater than equal to 3
Показать описание
Here dfa construction for language L=ab^na^m where, n is greater than or equal to 2 and m is greater than or equal to 3 is shown.
link to my channel-
link to data structure and algorithm playlist -
link to information theory and coding techniques playlist -
link to compiler design playlist -
link to Formal Languages and Automata Theory-
link to my channel-
link to data structure and algorithm playlist -
link to information theory and coding techniques playlist -
link to compiler design playlist -
link to Formal Languages and Automata Theory-
0:04:28
DFA for ab^na^m where n is greater than or equal to 2 ,m is greater than equal to 3
0:04:44
dfa example with solution | Part-3 | TOC | Lec-12 | Bhanu Priya
0:06:05
Minimal DFA | Length of Strings | a b^n a^m (n ≥ 2, m ≥ 3)
0:08:20
DFA for Language l={a^n b^m c^x ,where n,m,x are more or 0} | Theory of Computaion | Automata theory
0:13:33
Design DFA for L= a^m b^n / n is greater than or equal to 0 | DFA Design | TOC | Automata
0:12:00
Minimal DFA | Length of Strings | a^n (n ≥ 0) | a^n b^m (n, m ≥ 0) | a^n b^m (n, m ≥ 1)
0:08:54
Conversion of Regular Expression to Finite Automata - Examples (Part 1)
0:09:35
Lec-17: DFA for Even a and Even b | Even a Odd b | Odd a and Even b | Odd a Odd b | TOC
0:04:19
dfa example in toc | no of a ' s greater than equal to 1 and no of b ' s = 2 | Niharika...
0:14:04
Design DFA for L= a^m b^n c^p / m,n,p is greater than or equal to 0 | DFA Design | TOC | Automata
0:11:36
2.26 DFA Designing - No. of a=n(mod m) && No. of b=p(mod r) | Theory of Computation
0:07:59
DFA for a^mb^n where m+n is odd
0:03:51
DFA Construction | Theory of Computation | Language={a^m b^n|m=2,n=1} | Finite Automata | 1.19
0:07:26
Lec-12: DFA of all binary strings divisible by 3 | DFA Example 5
0:07:40
Minimal DFA | Length of Strings | a^n b^m, where (n + m) is Odd and n, m ≥ 0
0:05:46
dfa example with solution | Part-2 | TOC | Lec-11 | Bhanu Priya
0:08:47
DFA for the strings ending with b and of the form a^n b
0:05:13
DFA for a^nb^mc^p where n,m,p are greater than or equal to 0
0:10:46
Lec-68: Conversion from Epsilon ε-NFA to DFA with example | Eliminate Epsilon ε-moves
0:05:04
Lecture-12: Design DFA for L= {a^n b^m n,m is greater than or equal to 1} inTelugu | Neelis Galaxy
0:05:45
Design DFA for L= a^n / n is greater than or equal to 0 , n is not =2, n is not =4 | TOC | Automata
0:07:08
DFA Design | Accepts all Strings of (a,b) Ending with 'ab' | Automata Theory | TOC
0:02:08
65 theory of computation | dfa construction |minimal dfa on L={a^nb^m | n,m greater then equal to 1}
0:02:37
27 Theory Of Computation|Construct a minimal DFA such that Na(W)mod3 greater than equal to Na(W)mod2
Комментарии