Sequential Digits | LeetCode 1291 | C++, Java, Python

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September LeetCoding Challenge | Problem 19 | Sequential Digits | 19 September,
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[crankyinmv]

Thanks for that. I implemented this 2 different ways, neither of which was this. For the 2nd approach, I made an array of all the possible sequential numbers (there's only 45 of them) and returned the subarray which matched the low-high range.

[rajeshg]

Sir, would you mind doing explanation videos for weekly contest questions. Always stuck with hard problems and solution in "discuss" section are not very helpful for beginners like me :(

[surajkiranreddymothe]

Please Continue Doing Videos on Daily Leetcoding Challenge.

[moayyadarz]

thank you may god help you
keep going this nice series
you really help and motivate us to continue with you

[rishisharma]

My solution(doesn't require any conversion from string to number or number to string)
vector<int> sequentialDigits(int low, int high) {
long val=0, prod=1, i, num=0, prev;
for(i=0; i<to_string(low).length(); i++){
num = (i+1)+ num*10;
val += prod;
prod *= 10;
}
prev=num;
vector<int> res;
while(num <= high){
if(num >= low)
res.push_back(num);
num += val;
if(num%10 == 0){
val += prod;++i;
num = prev*10+i;
prod *= 10;
prev = num;
}
}
return res;
}

[ashutoshtiwari]

Sir is there any way that I can contact you . I am having some doubt so can you please co-operate .

[clashtm]

Why use 10-i???
string is of 9 elements so <=9-i; It is more intuitive

[Brijeshkumar-lkmt]

Sir, can you share your LinkedIn I'd, I would like to connect with you.
Thank you for everyday awesome content.