Prove that Sin 3A = 3 SinA – 4 Sin^3A

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In this video I've explained how to prove that Sin3A = 3 SinA - 4 Sin^3A.

Formulas used in this video
Sin(A + B) = SinA CosB + CosA SinB
Sin2A = 2 SinA CosA
Cos2A = Cos^2A - Sin^2A

  1. Competition Pandit
  2. Trigonometry
  3. IIT JEE Math
  4. Class 11 Math
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