Complex Numbers Class 11 | JEE Main & Advanced

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Dive deep into Complex Numbers with this comprehensive Class 11 session, tailored for JEE Main & Advanced aspirants. Explore fundamental concepts, solve challenging problems, and build a solid foundation to excel in your exams. Join us for an engaging and informative lesson that will enhance your mathematical skills and boost your confidence
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#ComplexNumber #ComplexNumbers #ComplexNumbersOneShot #ComplexNumberClass11 #JEE2026 #JEE #ArvindKaliaSir #ArvindKalia #JEEPreparation #JEENexus #ComplexNumberOneShot
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TIMESTAMPS
0:00 Introduction & Nature of Chapter
3:21 Index and Critical topics
7:01 Iota & Powers of Iota
16:53 Describing complex numbers & its Algebra
55:54 Conjugate of complex numbers
1:34:30 Argand Plane (Modulus and Argument)
2:00:49 Properties of modulus
2:58:07 Properties of Argument
3:08:26 Representation of complex numbers in different forms
3:25:17 DE-Moivre' Theorem
3:34:21 Cube roots of Unity

[Thenics_Aayush]

No argument,
Arvind sir One shot lectures are top notch. ❤️🗿

[BabulSingh-bx]

Sir physics ka lecture kab aayega class 11ke liye

[Shvgylraj]

Is it just me who needs 7-8 hrs to complete a 4 hr lecture?

[einsteinium]

THANKS ALOT SIR!!! I am OVERWHELMED by the way you teach ALL the concepts including ADV. LEVEL with such an ease, it directly goes in head! Literally I feel you are one of THE BEST MATHEMATICS TEACHERS in INDIA. MERA BHAI MERA BHAI 🔥. You made it easy for me to enjoy learning.

[_vokus_]

Sir iske baad sequence and series one shot kijiye na please 🥺🥺

[football]

Starting the lecture
Will complete with repetition aur sheet by tomorrow evening
Thankyou bhai ❤❤❤

[SakshiBidwe]

Who's watching this for IIT -JAM??

[plasticpurush]

1 subscribe = under 2k rank in jee advanced ❤❤❤❤❤😊😊😊😊😊

[rudraansh]

Sir please take one shot of sequence and Series

[Ayush-mzux]

Commerce with math students will like❤️

[AmanMatlani]

Sir Remark✅, questions in between✅ and worksheet ✅ basically everything done and dusted 👍 . Thank you bhai. ♥️

[Misama-sina]

2:23:34 Unimodular wala question done and dusted.

[BenStokes]

Significance of i : 7:10 ( i kabhi dikhega nhi, bas ye dimaag mein rkhna h ki i = √-1 )

🌟 Std step

1) 1:00:56 1:02:05 write z = x + iy (z nikalna ho from eqn, use this)
OR.
2) 21:55 31:29 36:52 (make out that the result/answer is a CN, say z which is = x + iy)

🌟 22:26 23:37 31:39 36:59 1:52:58 : in CN, 1 eqn gives two info (1st by comparing real part on both sides, 2nd by comparing imaginary part on both sides)

Imp Variety Q in Conjugate of CN : 1:00:37. (Put z = x + iy and then obtaining 2 info from 1 eqn)

1:15:05 1:19:02 1:19:56 : Conjugate mein power andar bahar ja skti h

Method to use info that CN (say z) is purely imaginary or real : 1:22:33 1:26:05 1:27:43 1:32:38 1:55:30 (z aur zconj. ka addn aur subtraction yaad kro and use accordingly as per q)
1:29:55. : Also use this property to comment upon Re(z) or Im(z) {har baar 0 ho, zaroori thodi h}

2:09:22 2:15:26 : Solving Tip - Aese q mein ek side bnane ki koshish kro, doosri side apne apne bn jaegi ( for eg here we created RHS by taking mod and sq in given eqn) 🌟 ie desired cheez ko create kro!!!

2:06:32 : Cubic in z - Find 1 root by hit and trial (like we used to do in a cubic in x) by putting values = i, -i etc.

2:16:05 : MOD chahiye toh mod apply kro ( to get eqn in |z| )

2:18:46 2:20:15 2:22:05 2:28:17:
1) Jab bhi MOD ke andar z baitha ho, sq it and use (z.zconj = |z|²).
2) MOD baitha h aur kuch smjh nhi aa rha, Sq it and use (|z|² = z.zconj)

2:31:42 2:32:23 2:34:47 2:35:45 : MOD ki value given ho (let |z| = a), toh use (z.zconj = a²) anyhow in asked expn

3:10:34 3:12:48 : Polar Form : |z|, theta pta h then we can write CN

[lilfrxstalr]

Sir bhagwan ke liye agla chapter snp le aao sirrr aapki bhot kripa rahegi 🙏🙏🙏🙏

[nameplease]

everything done and dusted, amazing lecture very easily explained...🥰

[TejasRor-emxx]

Yeah crystal clear
Mera bhai 😊😊😊❤❤❤❤❤❤

[arunkumawat]

1:54:36 Method -4 put z = i y ( iota* y) and then rationalize and put imaginary part equal to zero the we got answer...Plz do it in smart way it`s not a lengthy method

[joshuabell]

Sir at 1:07:20 .. We're getting x=+2 or -2 and y +1 or -1... But sir since we're using "X*Y=15"..doesn't that mean that X and Y need to have the same sign? And doesn't that also ultimately mean that x and y also need to have the same sign.... So aren't possible solutions for this equation (2, 1) and (-2, -1)? So the answer should be D(2) right?

[PranshuJha-cqcg]

Sir Complex number conjugate wala calculation done and dusted

[jadusir]

sir jaldi se sabhi chapter ke one shot daal dijiye Nov tak
syllabus Pura revise bhi karna hai