Ray diagram for image formed by a converging/convex lens step by step instructions

Step by step instructions of how to draw a ray diagram for a real image formed by a converging/convex lens. Suitable for GCSE Physics.

[NotTheDotDot]

I love how my teacher spent over 2 entire lessons trying to get this across the class, then this guy pulls up and does it better in a matter of 5 minutes
what a goat

[imsra]

thank you so much for this explanation! i understood so well in such a short time

[nguriimieze]

Oh yeah I now got the whole thing don't you some vids for nuclear physics?😢

[AarushLalaPingyang]

Sir, what about if it is at 1f??? Need some desperate help and chatgpt not very usefull 😀

[SameeraPatel-st]

No disrespect to my tutor but this is much clearly n better explained you should work in uni

[tunistick]

F' not F because the image focal point not the object's

[tunistick]

The calculation aren't really correct. The formula for calculation the magnification is:
γ=OA'/OA where OA' is the algebraic distance from the center to the image and OA is that from the center to the object

We can calculate OA' from this formula:
1/OA'-1/OA=1/f' where f' is the algebraic value OF'

thus:
OA'=1/(1/f'+1/OA)
OA'=1/(1/2-1/8)=8/3 cm

• OA'>0 => the image is real

Thus γ=OA'/OA=8/(3.(-8))=-1/3
And we have:
• γ<0 => the image is inverted
• |γ|<1 => the image is reduced/diminshed

We can actually deduce the height of the object too since γ=A'B'/AB too
thus A'B'=γ.AB=-2/3cm

Hence you're not correct A'B'≠-7cm but -0.666...cm