PYQs on Bounded Variation | Fully Short Cut tricks | CSIR NET 2011 to 2023

This lecture explains questios related to Bounded variations of CSIR NET 2011 to 2023

[rupesh]

Great sir I enjoy when you are solving questions within 15 sec. in almost every lecture. Thanks sir ❤❤

[shikhasarkar]

13:52 tan(3) to tan(8) is infinite for atleast one values as 3+(π/2)<8
So tanx+(1/(x-2)) not BV according to me.
Thank you sir

[priyanjalitripathi]

great so much for giving all concept of bounded variation in one video.

[loqxowe]

Your explanations and the way you clear the concept is just wow...❤

[sarojsi]

Good explanation with good collection 👍👍

[Prayosi]

These lectures are very good. Thank you so much sir.

[positivethoughts]

Thank you so much for this important video 🙏🏼...

[ChandanKumar-dnlz]

Excellent explanation... Outstanding....in just one hr lecture each and every thing got Cristal clear ....thanks a lot sir jee.

[professorragavan]

Thankyou very much sir. I did not know about a single concept of bounded variation. After watching your video, it is very useful to me. 🤩😍

[jkmathematics..jitendrakoh]

Thanku so much sir love from ❤❤ uttarakhand

[amankumarbehera]

It is very helpful for us sir... keep it up, we are with you ❤😊🙏

[madhavigandhi]

NBHM 2014 For last option sir, we can say f is bounded by f(0) and below by f(1) therefore it is bdd.

[KAREN-yepf]

27.22 Problem (b) x=1 is not in the domain itself how can we find tan (pi/2)=infinity and we say it's not BV sir ?

[nehajangra]

Mistakes in last bouned variation implies monotonicity
Monotonic + bdd is b.v. but ek nbhm k question main closed interval per monotonic diya hua h how it implies that function is of b.v.

[madhavigandhi]

Thank You very much sir, for guiding us selflessly.
Your videos are marvellous ! Very useful, clear and doubt solving.

[kunjkothiya]

At time 34:10. In this question A is correct option.

[RS]

❤❤❤ eske alawa kya hi likh den...kyuki sir se accha samjhane wala Aaj Tak dusra koi Mila nhi. Thank you sir. 🙏

[jaikmthomas]

@50:00 Sir if function is not continuous then need not be f is not reimann integrable

[celinjoseph-xs]

Very nice sir
Kindly give on continous and differentiability uniform continuity topic sir before june 2024 csir pleaseeee

[vishal-eztz]

at 49:41 function is not continuous only at 1 . Therefore discontinuity at only finite number of points this implies f is riemann integerable .Am i right? plz verify sir