Physics 68 Lagrangian Mechanics (4 of 25) Free Fall: Example

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In this video I will derive the position with-respect-to time equation of a simple free-fall problem using the partial derivative of Lagrangian equation.

Next video in this series can be seen at:
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I'm just a neighbouring citizen of Sweden, so I cannot present the Nobel for you, but please accept these virtual flowers from the lamemen of the physic-lovers, that are in gratitude for you service to make science indisgestible without signing up to Stanford/MIT/etc.

pelimies
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Hi At 4:31 you substitute +mg when you were supposed to substitute -mg. Am I wrong here? Thanks for great videos.

drlangattxdotnet
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As an undergraduate student, your videos are of tremendous help. Thank you so much for dedication of spreading knowledge! Love the videos.

auruxy
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I think you miss a minus sign in 4:30 in the force component.. thank you for these lectures

collegemathematics
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Sir please Do something about Hamilton

niranjanmahajan
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Love how you build up as you proceed with your lectures and i am so grateful for you existence.

CatsBirds
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Very well explained !
Thank you so much, Professor !
(from Belgium)

lucvelghe
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Explained in a skilled manner. Thanks!

Bhaumikpk
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2:28 "because this would require extra work and energy, and that is not going to happen"
What I tell my boss every time he requests me to do anything beyond the initial scope of a task

delusiveblaze
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Thank you! I wish professors make it this easy, your effort is deeply appreciated, my exam is tomorrow and you just saved me !

allaryyan
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I read the comments and your answer to the sign confusion. I am not sure I understand exactly the reason to switch signs. Great videos.

drlangattxdotnet
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Sir your lectures are just mindblowing...keep up the gud work...gud wishes from India..❤️❤️

subhamchandra
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Thank you for the wonderful lectures.. Do you teach in a University or somewhere similar?? If yes, your students are really lucky to have you.. ^^

snegamanjini
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Great explanation concise and clear.
One thing I will like to point out is that "g" is always -ve (i.e. g = -9.81 m/s^2) and gravitational potential energy is also always -ve. Hence F = -mg. This will give F=ma in the above example.

hasanshirazi
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very clear examples, can do this myself now!!

gerritkoenen
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michel I am lost when you writing the lagrangian the dL\dx is nagative but when u substitute into the lagrangian u leave that nagative and the negative of the lagrangian it self why u left it

gabrielgumede
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Hats off to this wonderful lecture from another physics teacher !!!

solidstatedevices
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that was amazing... BEHOLD the Power and Beauty of MATH!!

ptyptypty
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Thank you Sir for your explanation. I think that the sign of g is wrong, it should be (-) I think.

AN-zkkz
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hello! From the free fall you were saying the kinetic energy increases while potential decreases So how does the lagragian equal -mgy only

stephenobeng