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Integration by Algebraic Substitution.
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#Integration #by #Substitution
Substitution for integrals corresponds to the chain rule for derivatives.
Suppose that F(u) is an antiderivative of f(u):
∫f(u)du=F(u)+C.
Assuming that u=u(x) is a differentiable function and using the chain rule, we have
ddxF(u(x))=F′(u(x))u′(x)=f(u(x))u′(x).
Integrating both sides gives
∫f(u(x))u′(x)dx=F(u(x))+C.
Hence
∫f(u(x))u′(x)dx=∫f(u)du,whereu=u(x).
This is the substitution rule formula for indefinite integrals.
Note that the integral on the left is expressed in terms of the variable x. The integral on the right is in terms of u.
The substitution method (also called u−substitution) is used when an integral contains some function and its derivative. In this case, we can set u equal to the function and rewrite the integral in terms of the new variable u. This makes the integral easier to solve.
Do not forget to express the final answer in terms of the original variable x.
If you find this video interesting, kindly subscribe to my channel for more exciting Maths tutorials.
Substitution for integrals corresponds to the chain rule for derivatives.
Suppose that F(u) is an antiderivative of f(u):
∫f(u)du=F(u)+C.
Assuming that u=u(x) is a differentiable function and using the chain rule, we have
ddxF(u(x))=F′(u(x))u′(x)=f(u(x))u′(x).
Integrating both sides gives
∫f(u(x))u′(x)dx=F(u(x))+C.
Hence
∫f(u(x))u′(x)dx=∫f(u)du,whereu=u(x).
This is the substitution rule formula for indefinite integrals.
Note that the integral on the left is expressed in terms of the variable x. The integral on the right is in terms of u.
The substitution method (also called u−substitution) is used when an integral contains some function and its derivative. In this case, we can set u equal to the function and rewrite the integral in terms of the new variable u. This makes the integral easier to solve.
Do not forget to express the final answer in terms of the original variable x.
If you find this video interesting, kindly subscribe to my channel for more exciting Maths tutorials.
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