Frequently Asked Python Program 11: How To Search an Element in a List

Topic : How To Search an Element in a List

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[ramanaboinaharish]

n=[1, 6, 3, 5, 3, 4]
ele=100
if ele in n:
print("element found")
else:
print("not found")

[sensationalwolf]

list = [2, 6, 8, 9, 3, 7]

num = int(input("enter the number: "))

if num in list:
print(f"the number {num} is on the list.")

else:
print(f"the number {num} is not on the list.")

this is easy way.

[bharathi_balasubramani]

Sir..., Suppose we have to search more values in the given list how I Enter

[ЛашынНурбек-чс]

9 "Ә" Нурбек Лашын. Сабақты қапап отырмын🙂

[dharani_vlogs]

def searchelement():
a=[1, 2, 3, 4, 5, 6, 7]
b=int(input("Enter a number:"))
for i in a:
if b in a:
print("Element found")
break
else:
print("Element not found")
break
searchelement()

[palashcse]

I want to find @ in a list of string how can i do it

[lucifercoxi]

finally I got to know, why I was getting
item absent
item absent
item present

[visheshsingh]

mylist=[2, 4, 1, 3, 5, 54, 52, 11, 34, 56, 6, 54, 7, 9, 65]
num=int(input("Enter the no you want to search"))

for i in range (0, len(mylist)):
if mylist[i]==num:
print("Number found")
break
else:
print("not found")

[sasidharnaidu]

U could use else after for loop, instead of using the flag variable

[mcdonaldifill]

Could you write the code that uses a list containing three characters and then asks a user to enter a character. The code will then search the list to see if the entered character is in the list or not. If it’s not in the list, then the user is asked to enter a different character. This loop keeps repeating until the user enters a character which IS present in the list.

[akbotaavdkhan]

9ә сынып оқушысы Халаат Ақбота .Сабакты карап отырмын

[thericesquad]

you should put if I in my list not if I == mylist like this: