Trigonometry Review (2 of 5)

Part 1 (1-13): Convert between degrees and radians, graph angles in standard position, and find coterminal angles in both radians and degrees. Find the exact value (the ratio between the sides) of different special angles (30°-60°-90° and 45°-45°-90°) by evaluating the trigonometric function (sin, cos, tan, csc, sec, cot).

Part 2 (14-20): More evaluating questions continued from part 1. Find the trigonometric ratio given: (1) a point (x, y) on the terminal side of an angle in standard position, (2) a triangle, (3) another trig ratio. All answers are left as exact (simplified radical form).

Part 3 (20b-23): Using trig functions and inverse trig functions to find missing angles or sides in right triangles. Now we're using the calculator and approximating our answers.

Part 4 (24a-c): We leave the comfortable world of right triangles behind and enter a world with no 90° angles and no hypotenuses. So, we must use law of sines and law of cosines to find missing sides and angles and solve triangles. Beware of the SSA situation because it doesn't mean there is only 1 triangle possible; there might be two or it might not even be a triangle.

Part 5 (24d-25): We continue solving triangles with the law of sines and law of cosines. We also find the area of non-right triangles using two different area formulas.

[VickiLovesLink]

This is EXACTLY what i was looking for! Thank you so much :)

[sacae]

Wow! I learned Trig in an hour. Thank you so much for these videos :)

[davidtutorsmath]

@ifyolash You are welcome. Thanks for taking the time to say thank you.

[davidtutorsmath]

@sacae95 You're quite welcome! While I wouldn't say that cramming is the best way to learn trig, I'm glad that you now feel confident with it.

[davidtutorsmath]

@Halfpipesk8r You are right. In my hurry to rationalize, I used the 2 instead of 5. The Tanx= 2rt(5)/5.

[davidtutorsmath]

@MrKriminal27 While I do make plenty of mistakes (and I welcome corrections), #16 is correct as -rt(3)/3. Double check that you took the cotangent.

[davidtutorsmath]

@Halfpipesk8r I've corrected this now with an annotation. Thank you!

[phillipandrews]

"Thank you for taking the time to say thank you to [me] saying thank you." lol

[davidtutorsmath]

@cmiller8492 Thanks. Glad you found it helpful.

[MrKriminal]

sir in no 16 i think it should be negatine square root of three am i correct?