Sort the given string using character search | GeeksforGeeks

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create an array of 26 counts then run through the string once counting the number of each character; then run through the array of counts adding the corresponding character count number of times. The algorithm runs in 26 + n instead of 26 * n. Yes, you still have to append a character <count> times but it's still fewer iterations, and you can use string(count, chr); (in C++)

xf
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How can you compare string with integer????

Suraj-sirc
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It was good but if possible
Please share a better solution.

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