61. (a) Use the Product Rule twice to prove that if f,g, and h are differentiable, then (fgh)'

61.
(a) Use the Product Rule twice to prove that if f,g, and h are differentiable, then (fgh)'=f^' gh+fg' h+fgh'.
(b) Taking f=g=h in part (a), show that d/dx[f(x)]^3=3[f(x)]^2f'(x)
(c) Use part (b) to differentiate y=e^3x.

Calculus: Early Transcendentals
Chapter 3: Differentiation Rules
Section 3.2: The Product and Quotient Rules
Problem 61

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