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Motion - NCERT Exercises | Class 9 Physics
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✅ In this video,
✔️ Class: 9
✔️ Subject: Physics
✔️ Chapter: Motion
✔️ Topic Name: NCERT Exercises
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00:00 Physics Introduction: Motion
00:18 NCERT Exercises Question 1
05:48 Question 2
10:26 Question 3
12:02 Question 4
12:34 Numericals Questions 1
14:59 Question 2
17:13 Website Overview
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Points covered in this video:-
Question 1. An athlete completes one round of a circular track of diameter 200 m in 40 s. What will be the distance covered and the displacement at the end of 2 minutes 20 s?
Solution: Here, Total time = 2 minutes 20 seconds
= 2 x 60 seconds + 20 seconds
= 120 seconds + 20 seconds
= 140 s
Now, in 40 s, the number of rounds completed = 1
So, in 140 s, the number of rounds completed = 1 x 140 = 3.5
(a) Calculation of distance covered in 3.5 rounds
The diameter of circular track is given to be 200 m, so the radius (r) of the circular track will be half of it, which is 200/2 = 100 m
Now, Distance covered in 1 round = Circumference of circular track
= 2πr
= 2 x (22/7) x 100 m (Because π = 22/7)
= 328.57 m
And, Distance covered = 628.57 x 3.5 m
In 3.5 rounds = 2200 m
(b) Calculation of displacement in 3.5 rounds
The athlete makes three and a half rounds (3.5 rounds) of the circular track. Now, if the athlete start from point A (see figure), then after three complete rounds, he will reach at the same point A. and when the athlete again starts from point A and makes the remaining half round, he will reach point B (which is diametrically opposite to A). so, the displacement of athlete will be equal to diameter of the circular track which is 200 m. .
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