What is the limit of (sin x)/x? - Week 1 - Lecture 7 - Mooculus

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  1. Jim Fowler
  2. mathematics
  3. calculus
  4. mooculus
  5. math
  6. maths
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Комментарии
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Really appreciate your explain, which helps me a lot. Thanks.

AstralChen
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You have really awesome videos for math explanations, really enjoy the animations! Great job!

gdogvibes
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I'm sorry, but how do you know that cos x is less than (sin x)/x ? I've seen page 33 from the Mooculus, but I just don't get the last line where the reciplocals are taken. Can you please help me? Thank you a lot

Александр-зжг
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Thank you for the clear explanation. I love your enthusiasm. 

evamorales
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I saw how you used the Squeeze Theorem to prove the limit was one, but I didn't see how you showed that sinx over x was between cosine and one.

BruceRhodewaltofLQ
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I legit had to watch that four times before it registered.

thisisjXsh
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Granted, limit tends to 1 as x tends to zero.  But why doesn't it work when you work in degrees? tends to 0.017 when working degrees.  There's no reason why it shouldn't work in degrees.  Please help.

ChauTu