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[naveenmenezes]

Sir you are taking in three languages
English
Kannada
Hindi

[santoshchakrapani]

Someone pls send maths question paper pls I need to analyse

[KrishnaMurtiKrishnaMurti-ouuk]

Happy Birthday da and best friend for your birthday to your mother and my love you have to goa

[Rquas]

Series resistance: 2ohm*4 =8ohm
Parallel resistance: 1/2×4=2ohm
Series/parallel=8/2=4/1
He has clearly said "the same 'resistors' so it means 4 of them are now placed not just one.

[ssk__farm]

Please, maths answer and question sslc exam 2024.

[lathiaalathiaa]

Sir pls sent us question before a day so children can read for exam and I request you maths question review tomorrow

[prashantbudihal]

5th one answer is wrong. Let me explain:- they have given that the power of an electric heater is 2kW. They have also given that can it could be connected to 15 A with V= 220v. Let's calculate the power. We know that P=VI. So 220 multiply by 15 is equal to 3300. So the power is 3.3kW. So if we supply this much power to an electric heater having power 2 kW, it can't handle 3.3 kW of power that is 1.3 kW of power extra.

[superheros-shortz]

2nd one is wrong according to google its ans is b option😅😅😅

[GaneshCPattanshetti]

2nd answer : - 16:1 is correct answer

[DeepGraphics]

Sir in 5th question how would the heater works if the current supplied by circuit is 15A and the heater requires only 9.09 A. It would cause overloading.

[DeepGraphics]

2nd answer

  let me explain to you

In series
R = 2ohm

R1 + R2 + R3 + R4 = 2 + 2 + 2 + 2 = 8 ohm
Resistor in series = 8 ohm

In parallel

1/Rp = 1/R1 + 1/R2 + 1/R3 + 1/R4
= 1/Rp = 1/2 + 1/2 + 1/2 + 1/2
= 1/Rp = 4/2
= 1/Rp = 2/1
Rp = 1/2 ( Taking reciprocal)

Resistor in parallel = 1/2 ohm

Rs/Rp = 8/1/2
= 8×2/1
= 16/1
Hence Rs/Rp = 16:1