373. Find K Pairs with Smallest Sums | Leetcode | Medium | Java | Priority Queue

Thinking of a more intuitive solution for the given problem other than the one explained in the video, we can employ a strategy that involves prioritizing (u, v) pairs efficiently. Initially, we consider all pairs but encounter a Time Limit Exceeded (TLE) issue.

To overcome this, we introduce a priority queue and process elements based on their 'u' values. Once the priority queue has K elements, we disregard 'v' values when their sum surpasses the top element in the queue. This optimization is applied selectively, specifically when the number of elements in the priority queue reaches K.

This approach not only addresses the TLE concern but also streamlines the computation by eliminating unnecessary considerations of 'v' values, leading to a more efficient and concise solution.

It was asked in Amazon, Google and Microsoft in the last six months.

Other problems for practice:

[ritikshandilya]

Thanks for great content, Best part about your tutorials is that they are completely beginner friendly and solution is also very optimized . We need more such tutorials .

[coding_ss]

thanks ... I really like the way you created index keys of string with ", " separating the indexes for the hashset :D ... even in the editorial leetcode is using javafx.util.Pair class for this ... which I think will not work in a real interview.