Negative Exponent with Fraction

[provencallegaulois]

I'm 24 and I'm trying to learn about mathematics again, your videos help a lot. Thanks for the great work!

[robertmarmaduke]

Taught TESL in Phnom Penh and was walking home one day, saw a ground floor alcove, under a building, filled with students on benches. Naturally I stopped, and at the back, a teacher with a chalkboard was explaining partial differential equations. From my math background, just shook my head. These Cambodian kids learning rocket science, on wood benches in the shade, beside the road. Amazing!

[mohamadanis]

Each term divided by 1/a.
5/(1/a) - (1/a)/(1/a) gives me
5a - 1
Piece of cake

[Kittycat]

I could never understand higher math but his simplicity of explaining the equation even has me understanding. We need to go back to this type of teaching.

[youtubeuserdan]

I feel dirty for thinking "oh yeah then just cancel the 1/a" immediately.

[electronicsinstructor]

I love these bite-size math lessons. Thank you!

[Shovi_]

I like this guy, he's a good teacher.

[mnight]

I love math and had some great math teachers in HS. But I would have LOVED you as my math teacher!

[akshatgour]

I'm amazed how, much older people here consider this as something difficult, while students in India solve such questions when we are in 6th grade

[mohammadzaid]

There is never a bad or boring subject but there could be a bad teacher
And you sir and a great teacher
I never thought math could be simple easy and entertaining
Thank you

[ZeroSleap]

Another way to do it is to split the fraction to 5/(1/a) -(1/a)/(1/a)= 5a-1

[alanhurdle]

Ty, I like your videos it show how people are kind.

[jneal]

The most casual chalk holder I've ever seen.

Its like hes not even writing so much as waving his hand and the equations get solved. 😮

[paxton]

I’ve always learned that negative exponents can simply become positive and moved to the other side of the fraction.
In this example (5 - 1/a)
———— —-> (5 - 1/a)*a
a^(-1)

[timeonly]

One small, but important quibble... The original expression is meaningless when a=0 (because of the 1/a in the numerator and in the denominator); yet, the new, simpler expression (5a-1) is perfectly ok when a=0. To fix this, the final answer needs to include the stipulation that a≠0. If one were to graph the original expression, it would be a straight line of slope m=5 and a HOLE at (0, -1).

[nbecnbec]

(5-1/a)/a^(-1)
= (5-1/a) • reciprocal(a^(-1))
= (5-1/a) • reciprocal(1/a)
= (5-1/a) • (a/1)
= (5-1/a) • a
= 5a-a/a
= 5a-1

[ryanmahadeo]

Back in mi dayz mi teachers used that type of projector.

[pierrettebalazut]

OK cette fois ci je suis moins fatiguée.
J'ai compris la démonstration.
Ça apparaît tout simple.

[gleamofcolor]

you can use inverse method to simplify the equation instead of multiplying 1/a on both numerator and denominator

[garydaslug]

i have so much luck. youre teaching the exact stuff i have to learn rn here in switzerland and all the german-speaking teachers are hella trash haha
thabks for your content!!!