A-Level Edexcel Mechanics M1 June 2010 Q8c : ExamSolutions

[hazzers]

This is one of the hardest SUVAT questions I have seen, thank you for making it clear to me :)

[aukseg]

Hi, this has been of a great help, thank you!!! Could you explain though if we should ALWAYS assume the particle moves up after the string breaks when answering questions like these?

[karatemaster]

Surely you have to take U in the final suvat equation as being 0 since the particle B will have momentarily stopped once the string snaps?

[xRedRockerx]

It was because the question was "calculate the further time elapsed..."

[AlexJWesto]

The thing I don't get is don't you have to take into account the time for the particle B to rise up from the position where the string breaks?

[littledreams]

at 5.56 why is the u value 0.7 not 0 because I thought if a particle changes direction, its velocity is momentarily 0? thanks

[sully]

Why didnt u solve the question in stages tho? I hate damn pullys

[kingfaruq]

At around 5:25 on the second equation i've resolved downwards. i.e. in direction of movement. So my s is positive as is my a but that means i come out with +0.7t, does my u become negative for this to work? if so why?

[umair]

at around 6:06, why cant we assume that v=0 since B hits the floor. then instead of finding s(which is -1.175m), we can use v=u+at and where v=0, u=0.7, a=-9.8, finally find t.. but still i get the wrong answer..can you please correct me????

[fadi]

Whatever the exam is done, how'd you guys do?

[mahamudasultana]

thank you sooo much for uploading these videos