Integral of the Day 12.27.23 | Trig Integral | Math with Professor V

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Комментарии
Автор

Professor V, thank you for another excellent Integral of the Day. Professor V, I approach the integral the same way you did by rewriting (Cos^4 x) as (Cos^2 x)^2 in the denominator. By letting u equal to Cos^2 x and differentiating it and using the known Trig identity, Sin2x equal to 2 Sin x Cos x, I got the exact solution that you computed. All Calculus students should know/memorize the integral that is equal to the Arctan. The integral of 1/ 1 + u^2 du is equal to Arctan(u) + C. This is an error free video/lecture on YouTube TV with Professor V from Math TV.

georgesadler
Автор

Dear Professor V I hope you are well, wow what an outstanding video! Thanks a lot Professor V for a video. I am surprised by the way you did the part of 1/(1+u^2) you can recall it easy while I had to let u=tan€ and also rewrite the identity of (sin €)^2 +(cos€)^2=1 then divide everything by (cos €)^2 . I got the same here! What if in the exam the say find the derivative of the answer we got 😥 I will run away to save time😂 . Do you think that is possible to get in university mathematics exam ?

siyabongasedrick