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In the given figure, PQR is an equilateral triangle and QRST is a square. Then ∠PSR is
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In the given figure, PQR is an equilateral triangle and QRST is a square. Then ∠PSR is
Correct option is B)
QRST is a square
let side=a
PQ=PR=QR=a
∠PRQ=60∘(△PQR is equilateral )
In △PRS
PR=PS
∠PSR=∠SPR
(angle opp. to equal sides are also equal)
=x
∠PRS=60+90=150∘
x+x+150=180( sum of angle of △PRS)
2x=30∘
x=15∘
Correct option is B)
QRST is a square
let side=a
PQ=PR=QR=a
∠PRQ=60∘(△PQR is equilateral )
In △PRS
PR=PS
∠PSR=∠SPR
(angle opp. to equal sides are also equal)
=x
∠PRS=60+90=150∘
x+x+150=180( sum of angle of △PRS)
2x=30∘
x=15∘