Elimination reactions of haloalkanes

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Hydroxide ions just can't make up their minds, one minute they are nucleophiles the next they are bases! To clear up this confusion watch this video to find out how dissolving hydroxide ions in alcohol makes them undergo elimination reactions to make alkenes ready to use in plastics. Complete with mechanisms too! Woo hoo!!!
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You have my upmost praise, thank you very much. Videos like these will always continue to help future generations of chemist. You've made this topic seem like a breeze and concise. Once again, thank you

uchiha_kami
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Stuck in quarantine but I still have to do an organic test to send to the teacher. This really helped!

caitlyn
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You explain this so well. I have been studying A-level Chemistry for 3 years now and have never really understood mechanisms till now.
You make this all look so easy!
A big shout out to you for making these videos 👍👏

salmanqureshi
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This video was helpful.I will share it with my friends and even teachers in school.I would like you to post a video in which it shows the reagent and condition needed for all the organic reaction in A level. Thank you Sir,

priyanshgujarati
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have my CIE in three days and let me just say you've put my college to shame. great video!

sophiasyed
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I hate that...., A level questions are hard as **** book has 0 explanation about the concept/ way and my teacher is lazy as a pig...
You should make a book having your videos

gretawilliams
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Thank you so much reading from the textbook was hard to understand, but you made it so much easier to understand.

fnxznsd
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This is amazing, understood it really well

LaithzProducctionz
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Please reply as soon as possible. You said that if the solvent was ethanol then there would be an elimination reaction. However for your nucleophilic substitution video you said that ethanol is a condition for nucleophilic substitution with cyanide ions. Im very confused.


Either way, love your videos man

jamesdordan
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You are a lifesaver!! thank you so very much! :)

t
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very well explained
I understand it much better thanks to this video :)

salmanqureshi
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On the diagram (on the right-hand side), shouldn't it be CH3CH2CH2OH instead of CH3CH2OH for the nucleophilic substitution example? Amazing explanation, by the way.

yashaswar
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Thank you for making this so easy to understand👏👏👏

grishmaghimire
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Why does the the product of nucleophilic substitution have only 2 Carbon atoms while the original haloalkane and the product of Elimination have 3 Carbon atoms ?

A quick answer would be extremely appreciated and thank you very much for your hard work and dedication to help students.

theMadZakuPilot
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Thank you so much for these videos-! I've got my AS mocks after Easter and they've been super helpful. I just wondered, if you have an elimination reaction between bromopropane and sodium hydroxide, will the products include (H2O and NaBr) or (HBr and NaOH) and why?

KatieSmith-eq
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If its dissolved in an ethanolic solvent then doesnt that mean its nucleophilic because in your other video of nucleophilic sub with NH3 the conditions were warm, ethanolic solvent and excess NH3? im confused

lolasmith
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Please reply when you can.. Do we heat the reaction mixture under reflux for elimination?

Lax
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At the end of the video where you're explaining the geometric isomer formation you say E/Z, can you not say cis/trans due to there being a hydrogen atom attached to both carbons in double bond? Or am I confusing the concept? Thanks SO much for these videos btw

paigelewington
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Hi, thanks for the video, seriously really has helped me understand this so much. If you dont mind i have a question, at 4:20, the C-H bond is being broken as H is being donated a lone pair, so why don't we show this by a curly arrow from centre of covalent bond C-H to C; we seem to show that for C-Cl but not for C-H ; can you explain why?

godofwar
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Thank you sir for the explanation :), pls do reply when you are free. You've mention in the video that there will be equal chance of forming the isomers, but wouldn't there be more but-2-ene formed ??because it is more stable than the but-1-ene due to positive inductive effect of alkyl groups

callistachan