Q5. Prove that AB+CQ=AC+BQ Area (ΔABQ= 1/2 (Perimeter of (ΔABC)× R

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AB, BC and CA of triangle ABC touch a circle with centre 0 and radius R at P. Q and R respectively. Prove that:
(i) AB+CQ=AC+BQ (ii) Area (ΔABQ= 1/2 (Perimeter of (ΔABC)× R

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