(LEC-05) Principle of virtual work || Virtual Displacement || #msc #bsc

(LEC-05) Principle of virtual work || Virtual Displacement || #msc #bsc

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#principleofvirtualwork #virtualdisplacement
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[AkashKumar-tbx]

bringing back love for physics after jee. love you sir❤❤

[Weaversway]

Sir take either deta or phi negative because we are measuring both angle from one vertical line. Which means one should be positive and other be negative.

[ScienceAspect]

please upload more lectures of this series. very good explanation you provide

[Dforce]

d-theta===d-phy, as they have same direction and string is inextensible. Therefore, ans me negative sign nhi aayega sir as per me

[ashishthorat]

very nice and easily explained virtual work concept, Thank You, Sir.

[surojstudy]

I'm not entirely sure, but I believe J.C. Upadhya took θ from the normal to the radius, and also φ took from the normal to the radius. Therefore, θ - φ = constant, not θ + φ. In this case, dθ = dφ, and the expression w1sin(θ) - w2sin(φ) holds. Kya hai ho sakta hai sir

[basusahu]

Thanks for making beautiful video...
I have seen this video and you landed to a ratio of weight which is negative... First of all we must ask ourselves what is physical meaning of the obtained result? you will find this is ratio of weight and cannot be negative in any case... Then where is the flaw in solution?
You will find flaw lies at dphi and dtheta..just move two ball say leftward by infinitesimal angle then
dtheta = dphi in magnitude
if I consider dtheta in downward direction then dphi will be in upward direction

if you consider unit direction along the component of force ( downward & tangential to sphere) then
dtheta =-dphi

and now angle between force and infinitesimal displacement is zero for both side

solution of JC upadhyay is ok

[ronney]

31:40

w1/w2 = - sinΦ / sinθ

zyada sahi h kyuki isme aap angle ki value sign k sath rakh skte hain. So ye equation ek general form h.


Equation, w1/w2 = sinΦ / sinθ

me angle ko sign k sath nhi rakha ja skta. Isme bina sign k hi rakhna hoga.


Clockwise angle ka sign negative aur anti clockwise angle ka sign positive liya jata h as you already know.

[ash_patil]

sir it should be positive as phy angle is decreasing therefore we have to put delta(phy) as -delta(phy)

[vivekthakur]

Both the displaced angles are equal and with positive sign

[viku]

what i think is we should consider displacement of the two masses in opp dirction to one another and then only we can define delr1 and delr2 otherwise in the same direction they will be equal

[athiest]

I think we should consider the direction of angle according to the convention. Anticlockwise direction is treated to be positive . Then direction of òthita and òphi should be same

[mathrocking]

Sir IIT jam, jest, tifr keliye questions session

[RishiSharma]

Sir del theta- del phai equal to zero
Aapne plus kiye h

[AdwaithReddyKorpole]

Sir w1/w2 =sin(phy)/sin(theta) hi hona chahiye
Negative nahi ayega kyoki aap ne work done by w2 me delta r2(I.e phy) ko negative mana tabi toh work negative aa raha he . Aap phir se sign convention Kyo laga Rahe ho

For example if w1 and w2 are 1 and theta and phy are 90 then according w1/w2 = -sin(phy)/sin(theta
1=-1 aa raha he

[foziaafzal]

Thanks so much sir loving your channel from Pakistan

[tahirzaman]

Yours lecture delivery method is wow.
Sir I have question, as if the system is in equilibrium then virtual work is zero because of net force on the system is zero which is apparent to everyone, but if the system is not equilibrium the work done in virtual displacement will be zero or not. Moreover if it is equal to zero or not then what are it's physical meanings

[piyushvashisthamishra]

minus is beacuse sir you take two times the direction for solving the question in initial stage only if we take the delta r then their only we get desired answer beacause delta r cannot be zero if again put constraint we will endup with negative sign. and not get desired result as in book

[info-hub]

Sir why didnt we introduce the backword force that is pulling the blocks down along the inclined ledge you only considered the force due to gravity on both the blocks?

[jyotikigrihasthi]

Sir introduction to tensor pr bhi ek lecture bnaiye plzzz