Comptia Network+ N10-008 Practice Exam with Answers Pt. 1

Hey guys! I've been studying hard for my CompTIA N10-008 Network+ Certification Exam, and I wanted to make some videos while doing it. I hope that you can benefit from these practice questions and answers! I review all the questions and answers in the video for the Network+ N10-008, so I hope it is helpful to you! Hopefully you can follow along if you are also studying for your CompTIA Network+ Certification test.

If you do enjoy this video or find it helpful, please subscribe to my channel! Every subscriber means a lot to me! I will keep the nerdy content flowing for you guys. Thank you!

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Jump Around!
00:00 Intro
00:28 Discounted Network+ Voucher
2:19 Questions & Answers
46:51 Outro

[txkfyns]

Passed my Network+ exam in part because of your videos. At least a dozen questions were accompanied by your visage and voice and as a very visual learner I'm grateful I picked you! thank you!

[Fractalesque]

What I like is how you've left yourself vulnerable to making mistakes. Practically everything you got wrong, I got wrong too and was forced back to the training materials to fill in the holes in the knowledge. Thank you for allowing yourself to be not only this helpful, but also this open. My upcoming Network+ exam now seems more like a storm wave rather than a tsunami at this point.

[ivanjovanovic]

1.st step: take 1100 0100 divide it in nibbles and under each nibble write 8421
8421 8421
2nd step: All numbers under 0 you ignore so you are left with this
1100 0100
84 - - -4 - -
3rd step: For each nibble SEPARATE add those lower numbers and you will get 12 on 1 side and 4 on other.
in hex:
1=1 8=8 15=F
2=2 9=9
3=3 10=A
4=4 11=B So basically you got 12 that is "C" in hex and 4 that is 4.... aka C4
5=5 12=C
6=6 13=D
7=7 14=E

[Kmj-qsdf]

Q13. I noticed that the binary and decimal were both saying 196 decimal, so then divided the 196 by 16 (hex) and that gave me 12 remainder 4. The 12 when counting in hex = C (0123456789AB 'C' DEF) and the remainder of 4 gave me a hex value of '4' so the answer was C4. ..seems dividing by 16 and doing it this way is relatively uncomplicated and 'should' work every time ..My Network+ is coming up as soon as I can find the courage and spare the cash to sit it! Great content

[tommyhuffman]

On question 13, the Hex is only there for a shortcut. Each four digits in binary convert to one digit in Hex. This way you can work with smaller numbers: 1100 = 12 (0xC) and 0100 = 4 (0x4), so 1100 0100 = C4. That trick doesn't work with decimal. This is because 16 is a power of 2 (2^4 = 16), but 10 is not a power of 2 (2 raised to any power will not equal 10).

[nesibeannelerinenguz]

I wanted to write about question 13.

Binary System = 128 +64 +32 + 16 + 8 + 4 + 2 +1 = 255
We are looking at which numbers we can use to reach the number 196. I need one 128 for this. Then I need 64 and one 4 e. 128 + 64 + 4 = 196.
Then I distribute it as 8 digits and divide it by two.
1100 0100
Then I add the first part and find the letter C as decimal 12 and hexadecimal. If I then add 0100 for the second part, I get 4. So our answer would be C4.
Thank you for this fine skill.

[SplashIs_]

For anyone who was stuck on the binary and decimal part here are a few things I like to keep in mind that may help.

My understanding portion

Hexadecimal = Hex(6), decimal (10), six over ten, so keep in mind there are 16 digits we have to pay attention to. From 0 - 9, we can count it normally, the only difference is in 10 we convert to A and keep going to 15. For example 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 ---> (Alphabet now) 10(A), 11(B), 12(C), 13(D), 14 (E), 15(F), we don't go up to 16 because we started at zero.

From this we now understand two things, the numbering system in hexadecimals (1) and it being 16(2).

Hence, we use this understanding of it having a base 16, to our advantage in decimals. Meaning if we want to convert a decimal to hexadecimal we need to divide it by 16.

Binary = Binary (0 or 1), keep in mind for decimals they use the power of 2, because it's base 2. This is all the information we need to start our conversions.

Solving portion

Binary part: 1100 0100
Since we're using base 2, we'll use the powers of 2 to solve this (respectfully for each part).
2^0 = 1
2^1 = 2
2^2 = 4
2^3 = 8
(This is all we need to solve this problem here, and keep in mind if there are more numbers you keep on going: for example if it was 111100, you'd go up to 2^5)
0's mean off, so we don't need to add those parts in, only the parts that have a one to it. Because of this, we get 4 + 8 = 12. So lets organize all of this together.

Binary : 1100 0100 (Go from right - left, not left to right)
1100 = 4 + 8 = 12
0100 = 4
Now to convert it to hexadecimal we keep in mind what we learned earlier, 12 = C, so we put C. 4 isn't that high so we keep it 4 (only converting pass 9). Giving us: C4

Decimal part

This part requires less work and if you've ever programmed you'd notice it's quite similar to the % operator (remainder).
Since we understand that hexadecimal is base 16, we divide whatever the decimal is by 16, here in this case it was 196.

196/16 = 12.25
16 * 12 = 192, meaning we're left with a remainder of 4.
So out of this, we have two important numbers the 12 which we got from dividing, and the 4. We convert the 12 to hexadecimal which is C and leave the 4 alone getting
C4

lets do another problem, lets say it was 230.
230/16 = 14.375
16 * 14 = 224, we need six more to get to 230, meaning the remainder is 6.
We have two important numbers the 14 and the 6 giving us:
E6

[Tralfazz]

Thanks for this. This convinced me to pay for practice tests, cause now I see why they're valuable.
As an aside, while the test writers know a lot a networking, they definitely could work on their sentence structure.

Edit: I was trying to be nice, but sweet lord, I'm starting to think they just learned English. I can't read a quarter of these on the first try.

[PlatinumPlayer]

Someone has probably already said this here but for anyone confused about NIC Teaming, most Net+ courses call NIC Teaming "Link Aggregation". It seems like CompTIA wants you to call it NIC Teaming but its essentially the same thing or at least the same general concept as Link Aggregation. Always look up terms you don't recognize because more than likely its something you DO know but under a different naming convention. Classic CompTIA.

[civiprepper]

Q30 requires the borrowing of bits in the last octet. Therefore it cannot be A or E. B, C, and D are the decimal values for 1, 2 0r 3 bits borrowed. If you look up how many bits are required to subnet a class c address you will see it require 3 bits can create a maximum of 8 subnets and that you can calculate the decimal value of three bits to total 224, eg 128+96+32.

[mjblcmichael]

For question 30, in a class C subnet, you usually have 254 possible host addresses. To set up subnets within that host section, you have to borrow bits from the last octet of the address. Look up "calculating subnets." TLDR, you have to borrow 4 bits from the final octet. So instead of (255), it is (224).

[SRTPD]

Awesome video! Appreciate your use of the binary 1s and 0s to get the subnet mask or CIDR, it made that part of subnetting really easy for me. Didn't think of it that way. Thank you Vincent!

[civiprepper]

Q37 easy fast calculation> /26 means there is two bits borrowed for subnetting and 6 bits for host. Two bits decimal value = 192 eg 128+64

[tytussimmons]

You are doing great! I'm going to school for cyber security and information assurance through WGU and I like to expose myself to all learning, as in watching, listening, and doing. You're doing great work and bring amazing character into it! Much respect for what you're doing!

[budddmj]

Finished a college class and am taking a week to cram and get rdy for my tests watching this video in the car while I travel and studying at home. 5 days left wish me luck! Also I subscribed 🎉

[JaskaranSingh-iouj]

Your Videos are amazing, Its good for revision and boost up my confidence for the exam

[jamesbyrd]

27 is iffy.

The correct answer is port or link aggregation. It's basically the same as nic teaming, but for a switch. I have never heard anyone call it that.

44 is also wrong. It's at least 10km.

[JoseCoss]

Thanks, Im taking the exam tomorrow and I got almost a perfect score on these questions, so thats a good sign.

[ImTheMrFoxman]

You have probably figured this out yourself, but for others potentially wondering why that Hex answer was C4.. That's cause you start counting from 0 instead of 1. So 0123456789ABCDEF.

[Rachelxxc]

i love your personality 😂 got me laughing when im stressing about this test