Introduction to Degrees of Freedom

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I have an exam in my chemical engineering class tomorrow and now this concept is beginning to make sense. I thank you great sir.

matthewnesci
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I just wanna say that I am so happy that I came across this channel, Thank You for all of this!!

SimulationH
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You guys are saving a life.Thank you so much.

rrt
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Wish you guys were here when I was taking the chemical engineering introductory course ☹️

rooooooooooooooody
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can 100= m2 + m3 be considered an equation?

logabalanvanar
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if we use y in terms of x for the second equation, wouldnt that make one less unknownvariable?

naqiyaali
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In example 1can we write the fraction of C as y=1-x and take it as an equation ? in this case we have 4 unknowns, 3 independent variables and 1 equation. So DOF=0

ulviss
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For example2, there's no m1 on the chart and I wonder if this makes the example unsolvable ?

markyang
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I'd like to know. For instance, on the product of a stream if we have the mass flow of the solution and the mass fraction of component A and the mass fraction of component B, the formula (Xa+Xb=1) working that out should be understood to fall under “other equations”?

tshwa_nelo
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Why not 1 = -0.2-x-y? On the second example?

InfinityLRDL
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Thank you so much!
very good explanation (:

blackh
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+LearnChemE very good explanation. I am a fan of yours now ;-)

hassanasif
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sorry I am confused. why didn't u say : y = 1 - x - 0.2. like you did with z, to become z-1 for B???
i am looking for your help and explanation regarding this question thx q

peterserey
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can we get a word problem solved, cause the part on stream 3 were (1-x) is the mass of c/kg confuses me.

henslymazwayi
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hi, i'm a bit confused why you haven't taken 1-z as one of the equations

chiprecious
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sorry I am confused. why didn't u say : y = 1 - x - 0.2. like you did with z, to become z-1 for B????

mpotsengmasetla
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What if I have pressure and temperature as parameters

peteroludareoladejo
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How is m3 an unknown here? it is given that it's 0.1m1 and m1 is known so how is m3 an unknown?

architg