If displacement `x` and velocity `v` related as `4v^(2) = 25 - x^(2)m` in a `SHM` Then time

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If displacement `x` and velocity `v` related as `4v^(2) = 25 - x^(2)m` in a `SHM` Then time period of given `SHM` is (consider SI unit)
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Daru pike baat kar rahe hai Aisa lag raha hai

yahs
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Sir nahi samajha but I am trying and thanks sir

unknownk