Functions 5.6 The Sine Law and the AMBIGUOUS Case!

Quick review from grade 10 Sine Law lesson and a very detailed explanation of the AMBIGUOUS Case. Demonstration included!

[sabinamaruf]

I learned this a different way which was must easier for me so I'm going to share it here for those who are confused :)
Sine Law: sin A/a = sin B/b = sin C/c
(Where capital letters are the angles and lowercase letters are the corresponding side lengths)
Ambiguous Case Of Sine Law
• Happens when you're given two side lengths, but only one angle that is NOT in between the side lengths
• Means there are two possible angles
To solve an ambiguous case:
1. Find the unknown angle using sine law
2. Subtract the new angle from 180 degrees to get the second possible angle

[_Stickie]

I learn more from these 20 minute videos than I do from my 2 hour classes at school lol

[sabinamaruf]

Thank you for your videos! They're incredibly helpful, I am preparing for grade 11 next year!!

[tang]

For in case 3 in 14:42, should it be "a" is smaller and equal to "b"? :)

[victorialm]

hi ms,
I was wondering, In mrkennedy’s pdf tb answer key solution for number 7, why did he do sin40 degrees = h/399.8? (I understand how 399.8 was found)

[matchamarble]

I keep getting sin(102) x 10/sin30 = 22.016 but in the video it says 19.5. Im so confused on what went wrong.

[garryfitzgerald]

Well done, thanks! On reflection we can't see you work out the solution for the two triangle case just before the end of the vid, your camera was positioned too high, the two triangle casd is not in view.

[imkingelijah]

2:24, I thought it was supposed to be sin30 in the denominator not sin3. ????

[somilarora]

Can you please do question 7 & 8 page 319