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Prove that `(tanA)/((1-cotA))+(cotA)/((1-tanA))=(1+tanA+cotA).`
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Prove that `(tanA)/((1-cotA))+(cotA)/((1-tanA))=(1+tanA+cotA).`
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Prove that `(tanA)/((1-cotA))+(cotA)/((1-tanA))=(1+tanA+cotA).`
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class 10 trigonometry formula prove TanA. CotA =1 #math
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`(tanA)/(1-cotA)+(cotA)/(1-tanA) = 1+tanA+cotA = 1+secAcosecA`
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prove that tanA/(1-cotA) + cotA/(1-tanA) = 1+secA.cosecA
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Prove that `(tan A)/((1-cot A))+(cot A)/((1-tan A))=(1+ tan A+cot A). `
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The expression `(tanA)/(1-cotA)+(cotA)/(1-tanA)` can be written as :
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Prove that: 1/(Tan2A - TanA) - 1/(Cot2A - CotA) = CotA
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tanA/1-cotA + cotA / 1-tan A = 1+ secA cosecA #learning_mathematics #math
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prove by tanA/1-cotA + cotA/1-tanA=1+secA×cosecA
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1+tan²A / 1+cot²A = (1-tanA/1-cotA)² = tan²A
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