SAT MATH Problem Graphs of Polynomials

#shorts

Study the end behavior of polynomials and degree and this question is really easy. This video will help you review.

[gf]

Honestly, just look at the roots
X^2 shows that theres a root that doesn’t pass the axis and only bounces at 0 as its really (x+0)^2, then (X-2) shows root at 2, and (X+3) shows a root at -3.

[miguelmendoza]

And even if that's not enough to tell which is the correct answer, we can look at the multiplicity of each root, 3 and -2 are multiplicity 1, which means they cross the X axis, like a straight line y = x function would do. X^2 touch the x axis only in a single point.

[Sgth]

The graph can easily narrow down your choices between b and d. Then take a look at where 2 is. It's at 0. Choice B make sense because if you plug in 2, you'll get 0.

[jcplayz]

Much easier method: count the turning points which there are 3, so it is an x^4 graph with 4 points of intersection, x=0 is a repeated root so x^2(x+a)(x+b) is always going to be the graph, then reject D as it says (x-3) when we know it needs to be (x+3)

[imados]

Looking at the roots the graph crosses (-3, 0) and (2, 0) so A and B are the only answer, we replace x with -1 to see if the result is negative like the graph, we conclude B is the correct answer

[seroujghazarian]

The roots are x=0, x=-3, and x=2, thus, x, x-2, and x+3 are factors of the function. But since the graph is tangent to the line y=0 at x=0, thus x=0 is a double root, thus, x² is a factor of the function.
<=> y=x²(x-2)(x+3)

[matthewbyrd]

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[mohitsoni]

Put zero's from the graph in the equation and then put x<(-3) you should get a +ve value for y
Satisfies by B option

[vx_yazan]

Chose a random point in the graph for example x, y =2, 0 and go to the choises and substetud x and y with 2 and 0 this how i do it is my way good?

[abhigyakumar]

We know two roots are 2 and -3 so answer is one of A and B
But if we put x=-1 in A then we get
y is greater than zero which is not true
But if we put x=-1 in B we get, y is less than zero which is true
Therefore answer is B

[nick]

just put x as infinity and - infinity and see if the result goes positive or negative(no need to memorize any graph)

[susmitbhar]

Isn't this like 1 sec ans questions like c, d out immediately as roots dont match, a is cubic and the graph is not cubic so b is the answer

[Andrux]

Honestly, if you are really struggling on this problem on the SAT, just plug the equations into your graphing calculator.

[xzm]

Commenting before watching.
A
plugged in 0 to x and y, plugged in (-1) to x, voila

[tibofordeyn]

Dude u should immediately look at the places where the graph is zero as soon as you see equations written that way. It's way quicker and speed is important on SAT. Solved in about 10 seconds.

[parthasarathyc]

Meanwhile 15 year old 10th grade students in India doing these problems everyday just to somehow impress their parents

[mikulramesh]

What was the hardest math problem ever on an SAT?

[ichweinicht]

put 2 in options can't be c or d.
Now put -1 can't be A =>B is the answer as simple as that

[ismaelgomez]

You can't really tell because you just don't know where the intersections are. they had to make you know that.