Lecture 10 Kernel and Image of Linear Transformation

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I've been looking for a good explanations for 2 days. Now I really found one. THANK YOU VERY MUCH!!!

TreAsiatica
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Great explanation.. understood really well😊Thankyou very much sir!🙏🏻🙏🏻

aksharaverma
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Thank You soo much sir, great explaination very helpful....

gayatrijoshi
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so, dimImA+dimKerA should be equal to dimA before the linear transformation?

Y-
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why did you choose exactly "z" and "t" as free variables when finding basis of kernel of T. How do we find, what are the variables that should assign values.

sajithpriyankaragunawardan
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WHY SHOULD WE TAKE Z=1, T=0. SIR WOULD U PLEASE REPLY

SUDHEER
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hello, very good explanation, could you please upload a video with this exercise S = {x € R ^ 3 / x1-x3 = 0 ^ x2 = 0} and T = {x € R ^ 3 / x2 = 0} define a linear transformation f: R ^ 3 to R ^ 3 to verify Nu f = S ^ Nu (fof) = T

brunogreco
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why did we take z, t as 0, 1 and 1, 0. we could have taken other values

raunakthapliyal