Draw a square #python #coding #softwareengineer

[philstanton]

Dont worry guys, it’s actually just a one liner:

def square(n):
print((n * “#” + “\n”) + ((n-2) * (“#” + ((n-2) * “ “) + “#\n”)) + (n * “#”))

[groot]

Please keep making the video from basics to advance. It was very much interesting the way you teach. Thank you so much ❤

[agentotten]

You could also do the top and then the bottom portion outside of the for loop, as to avoid the if statement all together.

[arielsouza]

order = int(input("Insira um valor natural: "))
for n in range(order):
print('x ' * order if n == 0 or n == order-1 else 'x ' + ' ' * (order-2) + 'x')

[dot]

The problem with these tutorials or showcases of these problems on YouTube is that the person has probably seen it before many times. So they'll always has the perfect answer

[krishnanandjb]

def print_square(n: int):
print('#' * n)
for i in range(n - 2):
print(f"#{' ' * (n - 2)}#")
print('#' * n)

[DatNickNganGonVaDeNho]

move edge condition out of loop to upgrade your coding level to intermediate.

[Hacky]

I feel ur pain switching up the syntax ive done that too many times😅

[shaqib]

Nice man! I did not know that we can do this in that way in python

[shalevforfor]

You can give it list of points and just check if the point is in a list if it does add X

[DeseLoki-kmsu]

def DrawSquare(n:int)->str:
Square =[]
for i in range(n):
if i==0 or i==n-1:
Square.append('x '*n + '\n')
else:
Square.append('x ' + ' '*(n - 2) +'x '+'\n')
return ''.join(Square)

print(DrawSquare(10))

[aditichamsan]

Not able to get this else statement plz define this... Plz reply

[jmac]

def print_square(n):
a = " ".join("X" * n)
b = "".join(a.split())
c = " ".join(f"{b[0]}{' ' * (n -2)}{b[0]}")
print(a)
[print(c) for each in range(0, n -2)]
print(a)

print_square(5)

[dIancaster]

You're all ignoring the cleanest solution:
for x in range(n):
for y in range(0, n):
if x == n - 1 or y == 0 or y == n - 1 or not x:
print('X', end = "")
else:
print(" ", end = '')
print('')

[apollonir]

if ((i % (n - 1) == 0) || (j % (n - 1) == 0)) that will be enough except n=1

[josuetoledo]

That was one of the easiest one I have done.

[bryceblazegamingyt]

Writing the least understandable code speedrun

[darkmift]

Too many people defaut to if else when ternary exists

[Germisstucklmao]

Here's the best way to do this, imo

def print_rectangle(n):
print("X X X X X")
for each in range(0, n):
print("X X")
print("X X X X X")

print_rectangle(5)

[Pawlo]

# © Pawlo370
def kwadrat(x):
for i in range(x):
if i%(x-1) == 0:
print("X "*x)
else:
print("X "+" "*(x-2)+"X")

kwadrat(5)