Let's Solve🚀: Sequence and Series Questions🧾 With AK Sir | JEE 2022 [IIT JEE Maths] | Vedantu JEE✌

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Let's Solve🚀: Sequence and Series Questions🧾 With AK Sir | JEE 2022 [IIT JEE Maths] | Vedantu JEE✌. Hello Students, watch the amazing session on Sequence and Series JEE in this Let's Solve Series. Here Arvind Kalia Sir will take you through the Most Important Sequence and Series JEE Questions for JEE Main 2022 Preparation. This session will be very helpful for the students who are preparing for JEE 2022 Exams. If you want to score high in the JEE Maths exam paper, then this session will help you get more marks. So, watch the complete video, and let's get a better understanding of the Sequence and Series JEE.

About Teacher 👨‍🏫: Following his passion, Arvind Kalia Sir (Mera Bhai) joined this noble profession after doing M.Sc. in Maths from IIT Delhi.

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🚀 **IMPORTANT PLAYLISTS & SESSIONS:**

Here’s a quick rundown of what you’re about to learn ⬇️
✦ sequence and series jee mains
✦ sequence and series jee
✦ sequence and series jee mains questions
✦ sequence and series jee mains one shot
✦ sequence and series jee one shot
✦ sequence and series questions
✦ sequence and series questions for jee mains
✦ sequence and series jee questions
✦ sequence and series class 11
✦ sequence and series class 11 one shot
✦ sequence and series class 11 Vedantu

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Thank you so much guys for watching the video. We hope, this session will help you get a better understanding of the topic. We would love to get your feedback. Please do comment below in the comment section.
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Nta logic :
2021- 0 Boards + 4 Attempts =4
2022- 2 Boards + 2 attempts =4
Hence both are equal.

akshaygoud
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38:35
I came up with an elegant solution, Arvind sir if you are reading this please reply if I am right
Open the expression as it is by multiplying
We would observe all possible powers of 1/3 can be formed by multiplication
Hence, an infinite GP with r=1/3
Apply formula of sum, beautifully get answer C

k.ashvanth
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JEEVedantu
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1:14:51 can't we do it like this:
since S1 = 2n and S2 = 4n and the diff is given (1000)
then
S2 - S1 =1000, therefore,
4n-2n=1000
n=500
6n = 6*500
6n = 3000

syezaian
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These sessions are really useful for all students... 11th 12th and droppers too
Thank you Arbind sir ❤️

lakshya_
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Sir, how did you solve the quadratic in the 6th question.. ?? .. couldn't get it

oorjamahana
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Thank u sir for everything you had done for us🥰

adityaskeyworld
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Sir please is series me vo sabhi tarah ke questions cover kijiye jo jee mains me puche jaa sakte har variety ke questions 🙏

fact__know
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Sir aap sach may bahut accha padhate hai

H_a_r_s_H__K_u_m_a_r
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Wahhh sir ekdum maja agya. 12th mein jana ke bad ill keep revising problems like these

samyakgupta
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Amazing lecture sir, sir now I'm getting the concept...and sir my doubts are clear now....but sir I'm still not able to crack some of questions when it came to test, sir am I missing something? Plzz help sir🙏🙏🙏🙏🙏

gauravsharma
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please ask Pulkit Jain sir to start master classes for jee
he is a great teacher for math

RajatBisht
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This is a session which was very helpful for me and also give me a pretty confidence in this chapter

OrignalshoryaXgaming
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These sessions are really helpful....here teacher really teach for children's future thanks sirji...💜💜💜

tan_nu
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Sir sequence and series ka jo revision session hua tha, uska pdf upload nhi hua h

ShubhamBarnwal
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Sir i am not able to understand the question and solve it and i can't even understand the solution u gave sir what should i do

dhananjay
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Ek lecture karke aaya tha, 1st ques mein hi halat khrab 😂

mohammadzohaib
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In 24:46 cant we just use summation in calculater by putting ap term as n and gp term that is (1+1/50) with power n-1

tusharmahesh
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Sir muje kuch samaj ni aata aapke slove karai hue question😢

siddharth--
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These sessions were/are really helpful your explanation is very great and helpful sir🙌👍
There was no timepass and every question was worth it 👍🔥

Omkar-nqmo