10 Boys & Girls Round a Table (1 of 2: Simple Conditions)

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Why is it raised to 5, rather than multiplying by 5?

ConTejasMusic
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so glad i did the last question on my own and it turned out to be correct

hadijaffri
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Thank you for this
It has helped me a lot

kelsthevibe
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I don’t comment on videos much but thanks this helps so much

mustacheful
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Ahr dam, i thought i found what i was looking for, fixed binary necklace aka how many ways to arrange boys and girls around the table without differing which boy or girl.
(So that altering between boy and girl would have only 1 solution). It is so hard to find.

Anyway, just wanted to say that your lessons are brilliant. It is a wonder that you do not have more views, especially with that many subscribers.

awebmate
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Why is 5P5 times 5P5 divided by 10 and doubled or times two the answer for arrangements of boys and girls sit alternatly or same as 4! times 5!

erikaoliveira
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Why is the first example only 1× 9! ? I thought the first person could be one out of those 10 people so it is 10 ×... and he has 10 places to choose so 10×10×9! 😅

LRosch
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What would be the answer in items a) and b) if the seats were identified with different letters?

fernandocoelho
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Why aren't we counting the number of various different couples which can be formed

nabeelkhan
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Why is it not 10! ? I don't understand why it needs to be just 9!
If you're over counting because order doesn't matter, then why does order not matter only for 10 permutations? What is so special about those specific 10 permutations that doesn't occur in all the 9! rest of them

mulimotola