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Differential Equations | CET & JEE Competitive Exams | MATHEMATICS | Part 3 of 4
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In Part 3, we advance to second-order differential equations, a crucial topic for students preparing for CET, JEE Mains, and board exams. This session dives deep into solving methods for second-order equations, enabling you to handle more complex problem types that often appear in competitive exams. You’ll learn how to apply advanced techniques to solve equations with precision and speed.
Our approach combines theory and practical applications, showing you how second-order differential equations are used in various scientific fields. The detailed walkthroughs and expert strategies we provide will empower you to approach these equations with confidence, helping you improve both speed and accuracy in exams.
🔔 Stay tuned for the final part on application-based differential equation problems!
📞 Call us: 82775 00123
TIMESTAMPS:
00:00 - Intro
01:49 - The solution of 𝑒^𝑑𝑦/𝑑𝑥 = (𝑥 + 1), 𝑦(0) = 3 is
(MTG - EXERSICE - QUES 95 - Page no - 216)
06:54 - The solution of the equation (2𝑦 − 1)𝑑𝑥 − (2𝑥 + 3)𝑑𝑦 = 0 is
(MTG - EXERSICE - QUES 80 - Page no - 215)
08:53 - Solve the differential equation (𝑥 − 𝑦)² 𝑑𝑦/𝑑𝑥 = 1
(MTG - EXERSICE - QUES 74 - Page no - 214)
12:28 - Solve the differential equation 𝑑𝑦/𝑑𝑥= (𝑥 + 𝑦 + 1)²
(MTG - EXERSICE - QUES 76 - Page no - 214)
14:05 - . Solve the differential equation and find its particular solution 𝑑𝑥/𝑥+2 + 𝑑𝑦/𝑦+2
= 0, when 𝑥 = 1, 𝑦 = 2.
(MTG - EXERSICE - QUES 86 - Page no - 215)
16:18 - Solve the initial value problem 𝑥(𝑥𝑑𝑦 − 𝑦 𝑑𝑥) = 𝑦 𝑑𝑥 𝑦(1) = 1.
(MTG - EXERSICE - QUES 91 - Page no - 215)
#secondorderdifferentialequations #2ndpuc #12thcbsemaths #cet #jeemains #competitiveexams #boardexams #mathematics #deevigeclasses #problemssolving #examconfidence #karnataka #cet #mcq #mcqimportantquestions #midterm #midtermexam2024 #kcet #kcet2025 #kcet2024
Our approach combines theory and practical applications, showing you how second-order differential equations are used in various scientific fields. The detailed walkthroughs and expert strategies we provide will empower you to approach these equations with confidence, helping you improve both speed and accuracy in exams.
🔔 Stay tuned for the final part on application-based differential equation problems!
📞 Call us: 82775 00123
TIMESTAMPS:
00:00 - Intro
01:49 - The solution of 𝑒^𝑑𝑦/𝑑𝑥 = (𝑥 + 1), 𝑦(0) = 3 is
(MTG - EXERSICE - QUES 95 - Page no - 216)
06:54 - The solution of the equation (2𝑦 − 1)𝑑𝑥 − (2𝑥 + 3)𝑑𝑦 = 0 is
(MTG - EXERSICE - QUES 80 - Page no - 215)
08:53 - Solve the differential equation (𝑥 − 𝑦)² 𝑑𝑦/𝑑𝑥 = 1
(MTG - EXERSICE - QUES 74 - Page no - 214)
12:28 - Solve the differential equation 𝑑𝑦/𝑑𝑥= (𝑥 + 𝑦 + 1)²
(MTG - EXERSICE - QUES 76 - Page no - 214)
14:05 - . Solve the differential equation and find its particular solution 𝑑𝑥/𝑥+2 + 𝑑𝑦/𝑦+2
= 0, when 𝑥 = 1, 𝑦 = 2.
(MTG - EXERSICE - QUES 86 - Page no - 215)
16:18 - Solve the initial value problem 𝑥(𝑥𝑑𝑦 − 𝑦 𝑑𝑥) = 𝑦 𝑑𝑥 𝑦(1) = 1.
(MTG - EXERSICE - QUES 91 - Page no - 215)
#secondorderdifferentialequations #2ndpuc #12thcbsemaths #cet #jeemains #competitiveexams #boardexams #mathematics #deevigeclasses #problemssolving #examconfidence #karnataka #cet #mcq #mcqimportantquestions #midterm #midtermexam2024 #kcet #kcet2025 #kcet2024