The function f is defined by f(x) = ax^2 + bx + c, where a, b, and c are constants. The graph of...

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Bluebook Digital SAT Practice Test 6, Section 2, Module 2 (HARD), Question 22:

The function f is defined by f(x) = ax^2 + bx + c, where a, b, and c are constants. The graph of y = f(x) in the xy-plane passes through the points (7, 0) and (-3, 0). If a is an integer greater than 1, which of the following could be the value of a + b?

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Thanks, this method is way better than previous one. I am taking SAT on 24th August, do you have any recomendation, please?

Mr_Assierne

Thanks a lot! I’ve been watching your videos non stop for the past week and they are all insanely helpful!

ladaal

We can also use the vertex form.
a (x - 2)^2 + k
ax^2 - 4ax + 4a + k
Thus,
a+b = -3a
Just like in the video

Thus, all we need to show is that the “c” terms are the same.
c = - 21a (video)
c = 4a + k (here)
Is k equal to - 25a ?

Let’s put the equation in the video into the vertex form.
a (x - 2)^2 - 21a - 4a
K is indeed equal to - 25a

OverclockingCowboy

Could you explain the first part of the solution please? f(x) = a (x-7) (x+3) = 0

yeet

why do we eliminate the choice c and d? although a>1 it doesn't mean a+b is also greater than 1 isn;t?

suachoi

i dont understand the last part like the a-4a part and so forth

onedoorhrshy

how do you know it equals -3a when you have a-4a

youngstratus

Does come under algebra or advance maths

GeetaAkshara

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