EDEXCEL Topic 12 Acid-Base Equilibria REVISION

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Not the hero we deserve, but the hero we need

ahmedmersal
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You are a blessing, you’re videos manage to get me from an E to a B at the end of AS, and I’m finding a-level so much easier now thanks to your videos!!

cherrybullet
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thank you so much, these videos are incredibly helpful as i'm learning chem a2 alone.

xerp
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I was on a c last year in chemistry and now I am achieving A and high a stars I couldn’t have done this without you

elisaswaby
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All credits to you if in my upcoming A2 exams i get an overall A

nirmalkerai
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awesome video.easily understood buffers and you made these things look very easy. thank you!!

dhruvvarsani
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Thank you so so much I don’t think you understand how beneficial these videos are.

elisaswaby
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Your videos are amazing, they are incredibly helpful!!! Thank you

Ombremugofyasamal
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Thank you very much Mr Harris. These are very very useful indeed. I hope you are well.

st
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how may i express my thanks. this is amazing

yosufali
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Thank you so much!! I always use your videos, so helpful.

kailihuang
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Thank you so much for all these videos

johnsamangschannel
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About to go on a journey night before my exam

bholedg
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Your my idol. Seriously video helped so much!

jackstafford
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at 29:00 isnt the conc of H+ ions = 2 x conc of acid instead of conc of acid = 2 x conc of H+ ions?

shak
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Thank you so much for the video sir, It's an Absolute Life Saver. However I just have one doubt If you dont mind clearing up. At 1:22:29 Why is Dissociation of the Salt an equilibrium, Isn't it Fully Dissociating so It just be an Arrow point to the right. I'm Most probably wrong but it would be helpful if you could clear it up. Thanks alot

AliArif-yqin
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Dr.Freeze
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Can you make vidoes of worked solutions of recent past papers of edexcel ial chemistry unit 4, 5 and 6?

tanimahmed
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at 41:05 shouldn't the answer for the concentration of methanoic acid be 2.96x10^-11 moldm^-3 instead of 2.96x10^-3 moldm^-3

stardreamix
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I think at around 1:50:00 there's a typo - methanoic acid only has HCOOH, not CH3COOH - but it doesn't matter for the calculations right?

jeffreylau