Writing Quadratic Equations from Tables Without 0 for X

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👏 Amazing! Helped me to learn to help my daughter. We both watched. I guess you can teach an old dog a new trick.

repatasgallahar
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Have a test tomorrow, thanks for this advice.

mickeryx
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hello, I've been struggling with this one

x | y
0.01 0.06
> 0.18
0.02 0.24 > 0.12
> 0.3
0.03 0.54 > 0.12
> 0.43
0.04 0.96

also when x = 0, y = 0 using your reverse method.

2nd difference of this table is a = 0.12 ÷ 2 = 0.06
y = ax² + bx + c

and using algebra to solve for b gives me different b values.

b1 = 5.99 (0.01, 0.06)
b2 = 11.9988 (0.02, 0.24)
b3 = 17.9982 (0.03, 0.54)
b4 = 23.99 (0.04, 0.96)

thus, i cant pinpoint the precise quadratic formula on hand

so i used an online quadratic regression calculator and got this formula

y = 600(x)² + 1.0516e^-14(x) + -9.7145e^-17

Another way is to solve for a in y = ax2, which gives the expression
y = 600(x)² - the simplest formula yet

Does this imply that this procedure cannot be applied to some other table of values?

would you please explain this one?

highgglsgf
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what about if the numbers are skipping around??

gogzog
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Quick question, lets say the first points on the table were (5, 36), then how would you find c because it would be difficult to keep going back to 5, 4, 3, 2, 1, &0th term? Is there a formula or any way to find it out?

sara-fboi
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What happens if my y-intercept numbers are irregular? For example it goes down -3, and then -3 again, and then -9, and then -15?

bitquinn
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what id zero term si not at the same distance?

mohammadmahrous
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Are the relation is the same with equation?

stickimation
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what if it doesn’t have a 2nd difference?

alanakrantz