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`int sqrt(4-9x^(2))dx`

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`int sqrt(4-9x^(2))dx`
`int sqrt(4-9x^(2))dx`
Integral 1/sqrt(4-9x^2)
#shorts: int(sqrt(4-9x^2))dx
`int(dx)/(sqrt(4-9x^(2)))=?`
`intsqrt(4-9x^2)dx`
Trig Substitution | y=sqrt(4-9x^2)
How to solve integral 1/sqrt(4-9x^2) dx using Trig Sub
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`int_(0)^(2//3)sqrt(4-9x^(2))dx=`
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