The Cover-up method of Partial fraction decomposition

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In this video, I showed how to use the cover-up method of partial fraction decomposition. Best for rational functions with nonrepeated linear factors.
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I liked the explanation of why it works. I know the technique, but I am always distrustful of it, like it is a trick or I am misremembering it. Hopefully I will be able to trust it more better now.

kingbeauregard
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You can't cover up how good Prime Newtons is as a teacher! 🎉😊

punditgi
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"Let's get into the video" is my new favorite phrase

ounaogot
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This guy getting me interesting more.. I am 10th grader, I like learning/watching such advanced mathematics and this guy is a good place...

ItsJims
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Bro you are too good, respect and all the best from me

jaredlukumba
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I got 100% in my test thanks to you 🎉🎉🎉

Engineeringforall_
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You're just the best man 🤌
I appreciate your work 🙏

HarriSonn-ox
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This video was shown to my pre-cal class by the teacher, this video helped me understand a fast way to do this type of equation, thank you for teaching this. (My teacher also is envious that you have blackboard)

Totallyanormalsnake
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I'm learning this this semester so yippee

kiro
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your explanations are so good . thanks sir

ismaëlKanouotchiadzo-re
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In my opinion this cover up has some advantages when roots of the denominator are real and distinct
We need to remember which value we have already used
If we allow using complex numbers then there is residue method which gives us partial fraction decomposition
(Just like for inverse Laplace transform but without this exp(st) factor)

holyshit
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What brand of chalk do you use? Another great video. Great, full explanation.

TranquilSeaOfMath
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Thank you, Teacher!
İ love this video very much..

cggffffucfucd
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10:37 still don't get it, when you make x zero aren't you still dividing by zero even though the x in the denominator on both sides have been cancelled out, why does it work? is it because undefined=undefined works as a valid equation?

elai
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are there proof for the partial fraction decomposition?

jiahao
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I guess its the same thing as multiplying the entire equation by the original denominator so that there is no fraction, then just let x equal all the poles until you find values for A, B, C etc

Jason-otjv
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This is a great method, but for the sake of actually showing the workings to the problem.. That's where it's flawed. If i did this in a final exam situation, yes, it would save me time, but it cost me marks because i didn't show the algebraic operations to get there. Even though it just basic integration from there.Neat method though.

Videogamewrestling
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If you are partial fractioning 1/( x^2 p(x) ) -> A/x+B/x +C/p(x) for some poly p(x) then A = 1/p(0) and B = -p’(0) / p(0)^2 = -p’(0) A^2

chrisglosser
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Man with whole due of respect screw all my teachers they were idiots never did this

khairyalkhalidy
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Strictly speaking, you can't just plug zero in the last step as it must be that x is different from 0. However you can take the limit of both sides of the equation as x goes to zero which gives you the same result as plugging in zero.

NirDagan
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