Logic 101 (#47): Biconditional Tautologies

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When needing to prove a biconditional tautology in logic, there is a simple algorithm you should always follow. First, use a conditional proof to show one half of the biconditional. Then use a second conditional proof to show the other half of the biconditional. Finally, group those conditional together using biconditional introduction.
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Biconditional? More like unconditional...ly great videos. Thanks again for making and uploading all of them!

PunmasterSTP
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Q and -Q is a logical contradiction so it has to be false. So I know now that -(Q and -Q) is true. So applying disjunctive sillogysm to the antecedent of the flip-flopped implication that we assumed as true, the result is that P is true. If P was concluded as true then the conditional [P or (Q and - Q)] -> P is proved.

lea
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What if it is disjunction where both of the disjuncts are tautological biconditionals.

Handle
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can you please tell me how did you get if there is any premises or not?

mhabib