Number of Combinations for Girls and Boys to Form Sub Committees

preview_player
Показать описание
#Permutation_combination_made_simple #datamanagement_IBSL #Probability_Statistics #anilkumarmath #globalmathinstitute #permutationandcombination #permutation_combination #combinatorics #combinations #permutations #Probability #AnilKumar
Рекомендации по теме
Комментарии
Автор

Thanks 🙏.... very impressive teaching... keep it up

mondolawrancearmba
Автор

God bless u boss 😀👍❤. I really appreciate 🙌 it was explanatory and understandable 👌

ayomidebright
Автор

I have a problem. Understanding the combinations of these problems...for instance, in the question solved

If there are at least 2 girls, doesn't that mean the pr(2girls) =( 2girls and 2boys ) or (3girls and a boy) or (4girls and no boys)

Or does the fact that the group consists of 3girls and 6boys mean at least one of either group must be chosen?

daxscience
Автор

Thank you so much sir it is very helpful for me 😊

dhananjay
Автор

its good.. but when there would be more combination than this method will become long.. is there any shortcut formula for this kind of math?

crackone
Автор

There are 10 boys and 11 girls at a school. How many ways can the boys each choose a girl to take to the formal.

eddieegimbari
Автор

sir could you give me some hints to solve following problem?

Imagine you have 30 stamps of 205¥, 40 stamps of 82¥, and 30 stamps of 30¥.
Find how many values can be formed by using any combination of at least one of those stamps.

AbdullahAlMamun-hnsz
Автор

Can anyone answer ?
Q.A group of 6 players is selected randomly among a group of 11 men and 6 women. Determine the probability of exactly 4 men in the group?

kirtichaudhari
Автор

I didn't understand the 2nd one...
Why not fix 1st positions for girls
2 remain.
So now we have 1 girl + 6 boys
7C1 as ans?

harsh
Автор

For b four girl and 0 boy can be also I chance right?

karthikkumar