Python Program to Check Leap Year (Hindi) | Python Tutorial

WsCube Tech is a leading Web, Mobile App & Digital Marketing company, and institute in India.

We help businesses of all sizes to build their online presence, grow their business, and reach new heights.

All the courses are job-oriented, up-to-date with the latest algorithms and modules, fully practical, and provide you hands-on projects.

📞 For more info about the courses, call us: [phone], [phone]

✅ CONNECT WITH THE FOUNDER (Mr. Kushagra Bhatia) -

Connect with WsCube Tech on social media for the latest offers, promos, job vacancies, and much more:

--------------------------------------| Thanks |---------------------------
#pythontutorials #pythonprogramming #pythonprograms

[wscubetech]

😎Hey, thanks for watching! We’d love to know your thoughts/doubts here in the comments.

[learningcoder]

Mam here is an easy and alternative program to calculate this:

year = int(input("Enter year to check: "))
if (year%4==0) and (year%400==0) :
print("It is a leap year.")
elif (year%4==0) and (year%100!=0):
print("It is a leap year.")
else:
print("It is not a leap year.")

[indrajitkumar]

Here's an easy way to do this
year=int (input("Enter a year "))
temp=year//100
if temp%4==0:
print (year, "is a leap year")
else:
print (year, "is not leap year")

[shikhasolankistartforeverl]

Greatest videos it very helpful for bigners

[GoogleAndroidSmart]

Success is the result of perfection, hard work, learning from failure, loyalty, and persistence ?

[factstime]

Mam it can be done with simple program than this. There is no need to write such conditions
[n=int(input("enter any year = "))
if n%4==0 :
print (n, " is a leap year")
else:
print(n, " is not a leap year ")]

[ALEX_Edts]

try this:
a=int(input("enter year"))
if(a%4==0 and (a%100!=0 or a%400==0)):
print("its a leap year")
else:
print("noooo")

[subhashchandra]

Year = int(input("enter a year: ")

If (year % 400 == 0) and (year % 100 == 0):
print (year, "is a leap year")
elif (year % 4 == 0) and (year % 100 != 0):
print ( year, "is a leap year ")
else ( print, "is not a leap year")

[RishiRajxtrim]

6:15
No need to use "and (year % 100 == 0)" in line 3 of program code

[Sathvikachava-hnzf]

Import calendar
Print(calendar.isleap(2020))

O/p true

[AayushSoni-]

Year = int(input("Enter the Year about which you want to know wheather it's a leap year or not: "))
if Year%4 == 0:
print("The year give by you is a leap year")
else:
print("The year give by you is not a leap year")

is that true??

[xyz-ubqo]

Madam faltu me itne saare conditions lagaye. Agar / 4 == 0 karte. To hi condition satisfy ho jata

[soumyanandan]

Here is an easy way to do this:


Year=int(input("Enter the year"))
if Year%4==0 and Year%100!=0 or Year%400==0:
print("It is a leap year")
else:
print("It is not a leap year")

[stxyfcb]

Hello maim mera question ye hai k humare phone mein do tarah ki ip show hoti hai aik to phone ki settings mein aur dosri agar google pe my ip likh k search karein to, to kon c ip pe koi bhi attack perform ho sakta hai, phone ki settings wali ya jo google pe my ip likh k search kartay hein plz reply

[GalaxyCookies]

Even Dr. Angela failed to explain this concept the way you have, in a simple and easy way.

[ashifshaikh]

year = int(input("enter a year:"))

if (year % 4 == 0):
print(year, "is a leap year")
else:
print(year, "is not a leap year")

[ihaveitinme]

years=int(input("Enter Last Year till you want to see is that leap year or not:"))
for i in range(1999, years+1):

if i%400==0 and i%100==0:
print("Leap Year :", i)
if i%4==0 and i%100!=0:
print("Leap Year :", i)
# else:
# print("NOt Leap Year :", i)

[bikibharali]

x = int(input("Enter the year: "))
if x%400==0 or x%4==0:
print(f"The year {x} is a Leapyear")
else:
print(f"The year {x} is not a Leapyear")

[simpleguy]

Whats wrong in this method pls anybody explain

Year = int(input('enter a year: ') )
If(year % 4 == 0) :
print(year, "is a leap year) else:
print(year, " is not a leap year)

[Hamadkmehsud]

its simple if num = int(input("Enter a year: "))
if num % 4 == 0:
print(num, " is a Leap year")
else:
print(num, " is not Leap year")